How to make array with first values of matrix
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Hello to all,
I have a matrix for example like this: [1 2 3 4 5 6 7 8 9 10;2 2 3 3 4 5 5 2 3 3]' the first column represents time, the second ID of time. I need to make a cycle which goes through the matrix and takes the first time value from the group of ID of time.
So in this case the result will be: [1 3 5 6 8 9].
unique function is unfortunately not helpful in this case because the groups of ID of time might repeat.
Thank you very much
Filip
1 件のコメント
Jan
2018 年 2 月 22 日
Do not post multiple threads for one problem. See https://www.mathworks.com/matlabcentral/answers/384217-how-to-make-an-array-with-specific-matrix-values
回答 (1 件)
C.J. Harris
2018 年 2 月 22 日
% Input
A = [1 2 3 4 5 6 7 8 9 10;2 2 3 3 4 5 5 2 3 3]';
% Result
B = A([boolean(1); diff(A(:,2))~=0],1);
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