How to terminate simulation and output timesteps to termination

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Colin Lynch
Colin Lynch 2018 年 2 月 20 日
Hello everyone!
I am attempting to count the number of time steps it takes for a simulation to reach equilibrium, and once its there to terminate the simulation. Here, the simulation reaches equilibrium when n(t+1) = n(t) AND when S(t+1) = S(t). The following code runs the simulation until t = T, but I want it to stop when it reaches the above conditional and then I want it to output eq = t where t is the amount of time it took to reach equilibrium. Does anyone know how to make this happen, as this code is spitting out errors?
function [n, S] = simulate_dynamics(n0, S0, dt, T, A, B, C, D, beta, thetaI, thetaC, lambda, alpha, K)
eq = []
S(1) = S0;
n(1) = n0;
for t = 1:T
pStart = A + B * (S(t).^2./(S(t).^2 + thetaI.^2));
pStop = C + D * (1 ./ (1 + exp(beta*(S(t)-thetaC))));
n(t+1) = n(t) + dt * (pStart * (1 - n(t)) - pStop*n(t));
S(t+1) = S(t) + dt * (lambda*S(t).^alpha - K*n(t));
% keep both variables inside [0 1]
if S(t+1) > 1
S(t+1) = 1;
end
if n(t+1) > 1
n(t+1) = 1;
end
if S(t+1) < 0
S(t+1) = 0;
end
if n(t+1) < 0
n(t+1) = 0;
end
if n(t+1) = n(t) & S(t+1) = S(t)
eq = t
return
end
end

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