how do i store a matrix value inside a parfor loop?

I wanted to use the A matrix outside the parfor loop for further computation, i get an error stating "cannot run due to way variable A", is there any solution to this problem ??is there any other way to save the matrix???

thank you

N=50;
parfor n=1:Nc
    b=rand(300,103);
    [Q,R]=qr(b,0);
    A((n-1)*(N+1)+1:n*(N+1),:)=R
end

Answer 1

[Greg]

Pre-allocate A to store each R along the third dimension, then reshape it outside the loop. Iterations of parfor can't use indexing that depends on other iterations of the loop (i.e., n-1).

A = zeros(N+1,numColsofR,Nc);
parfor ...
  A(:,:,n) = R;
end
reshape(permute(A,[1,3,2]),[],numColsofR);

[Naveen kumar Elumalai]

thank you so much for the answer !!

[Greg]

Happy to help.

[Naveen kumar Elumalai]

This really worked out

[ahmad eldeeb]

What if zeros will consume large memory?