Error says "Subscript indices must either be real positive integers or logicals"

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zero
zero 2018 年 2 月 14 日
編集済み: Sam Chak 2023 年 11 月 1 日
x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 9, 9, 8, 7, 6, 5, 4, 3, 2, 1];
n = -9:9;
x1 = 5*x(n-2) - 3*x(n+4)
Array indices must be positive integers or logical values.
How to remove this error?
  1 件のコメント
Sam Chak
Sam Chak 2023 年 11 月 1 日
編集済み: Sam Chak 2023 年 11 月 1 日
What is variable n? It seems that n indicates the relative position (left and right) from the mean of the data set x, which is an array. In array indexing in MATLAB, the sequential position are assigned as positive integers that begins from 1 (Python indexing starts at 0). This is the Rule in MATLAB.
So, you need to play with a little bit of arithmetics in your head, just as shown by bhai @Arun.

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回答 (1 件)

Arun
Arun 2023 年 11 月 1 日
Hey,
here, the variable 'x' has index values ranging from 1 to 19. So to remove the error keep the index value with in that range of 1 to 19. For n-2 and n+4 both to be in range 1 to 19 the supported value for are in range 3 to 15. You can use the following code:
x = [1,2,3,4,5,6,7,8,9,9,9,8,7,6,5,4,3,2,1];
n = 3:15;
x1 = 5 * x(n-2) - 3*x(n+4)
x1 = 1×13
-16 -14 -12 -7 -2 6 14 22 30 33 36 34 32
another workaround can be to restructure the equation with respect to the size of 'x', one possible way is:
x = [1,2,3,4,5,6,7,8,9,9,9,8,7,6,5,4,3,2,1];
n = -9:9;
n = n + 10;
x1 = 5 * x(n)-2 - 3*x(n)+4
x1 = 1×19
4 6 8 10 12 14 16 18 20 20 20 18 16 14 12 10 8 6 4
Hope this gives you an idea to proceed.

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