I am having trouble with Taylor approximation to e^x at 0

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Erol Ozkan
Erol Ozkan 2018 年 2 月 11 日
回答済み: ag 2024 年 10 月 3 日
function y=myexp(x,n);
%this is my first function
%y is the n-th order Taylor approximation to exp(x)
%x is a scalar; n is positive integer
y=1;
term=1;
for k=1:n %n is a scalar
term=term*x/k;
y=y+term;
end
I am taking this error.
Not enough input arguments.
Error in myexp (line 8) for k=1:n %n is a scalar
what is wrong with that?

回答 (1 件)

ag
ag 2024 年 10 月 3 日
Hi Erol,
The error you are encountering arises because the variable "n" has not been initialized. As a result, the line
for k = 1:n
generates an error since "n" is undefined.
To resolve this issue, you need to ensure that "n" is properly initialized before it is used in the loop. To do this is you will have to run the script by including a call to the function, and pass the necessary values when invoking the function.
The below code snippet demonstrates how to achieve this:
y = myexp(1, 10)
y = 2.7183
function y=myexp(x,n)
y=1;
term=1;
for k=1:n %n is a scalar
term=term*x/k;
y=y+term;
end
end
Hope this helps!

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