Function input
古いコメントを表示
Hello everyone,
I know this is simple but I just can't figure it out by myself now.
I'm trying to create a function integrator, which asks the user to type the function to be integrated. I tried to use
g = input ('Enter function to be integrated: ')
f = @(x) g;
but MATLAB refuses it with Undefined function or variable 'x'. But how can we define x before so that f wouldn't get immediately evaluated?
Thanks a lot in adavnce!
回答 (2 件)
per isakson
2012 年 5 月 12 日
Try
string_input_by_user = input( .....
string_input_by_user = 'sin';
foo = str2func( ['@(x)', string_input_by_user, '(x)' ] );
or better
foo = str2func( ['@', string_input_by_user ] );
these two variants work
>> foo(4)
ans =
-0.7568
--- 2010-05-13 ---
Divide and conquer. One thing at a time. What exactly does the user input? Assume the user inputs the tree letter string "sin". Thus, the value of
string_input_by_user
is
'sin'
Then you can create a function_handle
foo = str2func( ['@', string_input_by_user ] );
and make a test
>> foo(pi/2)
ans =
1
>> foo([ 0 : pi/4 : pi+eps] )
ans =
0 0.7071 1.0000 0.7071 0.0000
If the user inputs the six letter string "sin(x)" it's a bit more tricky. You can create a function_handle
foo = str2func( ['@(x)', string_input_by_user ] );
The problem is that the user might input "sin(y)".
Expression
In Matlab "47*x" is an expression not a function. Make your code work with functions first. Then return to expressions.
The Question, Increasing of speed in numerical calculation, shows how to use expressions. However, there is some noise.
btw. Do you step through the code with the debugger and inspect the value of the variable?
4 件のコメント
Nina
2012 年 5 月 12 日
Walter Roberson
2012 年 5 月 12 日
Are you using a very old MATLAB, before there was support for anonymous functions?
Please show your current code.
Nina
2012 年 5 月 12 日
Walter Roberson
2012 年 5 月 12 日
string_input_by_user = input( ....., 's')
mohammad reza
2016 年 7 月 12 日
0 投票
now that you have got a user defined function, how can u integrate the function in the script? (with out limit)
1 件のコメント
Walter Roberson
2016 年 7 月 16 日
Indefinite integration requires the Symbolic Toolbox int() function
カテゴリ
ヘルプ センター および File Exchange で Startup and Shutdown についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!