Expanding a double array
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Hi Everybody,
I would like to solve this problem in the smartest way.
I have for example this column vector A=[3;5;6;4;...;2] and I would like to obtain another column vector like this B=[1;2;3;1;2;3;4;5;1;2;3;4;5;6;1;2;3;4;....;1;2], so B would be given for every natural number from 1 to every single element of A; an how can I reach this result?
I thought to start like this: B=1:A, but I get only B=[1;2;3]...any idea?
Thanks!
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回答 (1 件)
vijaya lakshmi
2018 年 2 月 8 日
Hi Giovanni,
I understand that you want to create a column vector which contains consecutive numbers, from 1 to every single element of A.
In this command "B=1:A", only the first element of A is considered.
You can try the following code snippet, to get the expected result
A=[2;4;3;5];
B=[];
for i=1:length(A)
B=vertcat(B,(1:A(i))');
end
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