how to use""\langle〈 and \rangle 〉 "" in matlab?

20 ビュー (過去 30 日間)
PLACEIUS NISHIGA G
PLACEIUS NISHIGA G 2018 年 1 月 31 日
コメント済み: PLACEIUS NISHIGA G 2018 年 1 月 31 日
the function is used to convert the binary sequence into 24 integers in which each one is produced by 8 binary bits.
  2 件のコメント
Jan
Jan 2018 年 1 月 31 日
Please explain, in which format the input "binary sequence" is available.
PLACEIUS NISHIGA G
PLACEIUS NISHIGA G 2018 年 1 月 31 日
sir ,I write a code but the final ans E contain two different matrix array size that is the combination of both E2 and k2 .I cannot convert into a single binary matrix. The binary sequence is converted into 24 integers in which each one is produced by 8 binary bits.please execute the code and if you find any different idea please inform me as soon as possible.
if true
clc;
clear all;
close all;
img = imread('cameraman.tif');
c=img';
d=c(:);
[W,L]=size(img);
k=randi(192,1,192);
syms k1 t
for i=1:4
k1=k(((48*i)-47):(48*i));
a1 = symsum(k1*(2^(t-(48*i)+47)),t,((48*i)-47),(48*i));
a=a1/(2^48);
end
for x=1:2
r(x)=mod(prod(a*(2^48)+a(x)),0.4)+3.6;
C(x)=mod(prod(a*(2^48)+a(x+2)),1);
end
C1=C(1);
C2=C(2);
for y=1:[W,L]
if y==1
C(y)=C(x);
else
if y~=1&&C(y-1)<0.5
C(y)=0.5*(r(x)*C(y-1));
else
if y~=1&&C(y-1)>=0.5
C(y)=0.5*(r(x)*(1-(C(y-1))));
end
end
end
end
for y=1:[W,L]
if y==1
E1(y)=d(y);
else
E1(y)=mod(d(y)+floor(C(y)*(10^13))+d(y-1),256);
end
end
for y=1:[W,L]
if y==[W,L]
E2(y)=E1(y);
else
E2(y)=mod(E1(y)+floor(C(y)*(10^13))+E1(y+1),256);
end
end
E2=E2';
Q=sum(E2');
Q=sym2poly(Q);
for j=1:192
q=dec2bin(Q,j);
kb=dec2bin(k,j);
end
kb = kb(randi(size(kb,1)),:);
k2=xor(q,kb);
E=[1,(W*L)+24];
E={k2,E2}
%E=bin2dec(char('0'+reshape(bits, 8, 24).'))
end

サインインしてコメントする。

採用された回答

Walter Roberson
Walter Roberson 2018 年 1 月 31 日
bin2dec(char('0'+reshape(bits, 8, 24).'))
... but what does this have to do with the angle brackets?

その他の回答 (0 件)

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by