M(t)=M(0) × e^(-t/T) + S × T × (1 - e^(-t/T)) How can I plot (T,M) graphic in MATLAB?

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FURKAN CEVAHIR
FURKAN CEVAHIR 2018 年 1 月 11 日
回答済み: FURKAN CEVAHIR 2018 年 1 月 11 日
M(t)=M(0) × e^(-t/T) + S × T × (1 - e^(-t/T)) How can I plot (T,M) graphic in MATLAB?
  1 件のコメント
ANKUR KUMAR
ANKUR KUMAR 2018 年 1 月 11 日
Which variables are the constants? t will vary with the every loop and T might be constant. What is the purpose of plotting T vs M.

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FURKAN CEVAHIR
FURKAN CEVAHIR 2018 年 1 月 11 日
編集済み: FURKAN CEVAHIR 2018 年 1 月 11 日
Actually, I want to catch the graphic just like that is in the photo attached. FYI:(T=1/k)

その他の回答 (2 件)

ANKUR KUMAR
ANKUR KUMAR 2018 年 1 月 11 日
According to the equation written in the image,
clc
clear
m_zero=5;
S=25;
k=2;
for t=1:500
as(t)=m_zero*(exp(-k*t))+(S/k)*(1-exp(-k*t));
end
plot((1:500),as)
I have taken m_zero as constant (you can change as per your theory).
I have taken S and k also as a constant randomly. Fix your constant and go further.

FURKAN CEVAHIR
FURKAN CEVAHIR 2018 年 1 月 11 日
What do you think, Without constants as parameters in the graphic, how was the graphic in the picture plotted? Thanks.

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