How to compare elements of rows within cell array?

Hey All ... I have an array 'array1'. I want to compare each elements of array1 with other elements.

    array1= {[1,2,3,8];[1,6];[1,2,3];[1,5,6];[2,4,5];[1,7];[2,8];[2,3,5,7,9]}

e.g. first elements is array1{1,1}={[1,2,3,8]}

All these values 1,2,3,8 will be compared with all other elements of array1 one by one. And find out where that value is present in other elements of array1, index of that row will be saved in resultant array.

    ResultantArray{1,1} = {[2,3,4,6];[3,5,7,8];[3,8];[7]} % e.g. [2,3,4,6] is result of comparing '1' with others and 2,3,4,6 are rows where 1 is present in array1. 
    ResultantArray{2,1} = {[1,3,4,6];[4]} % similary [1,6] are compared with others and {[1,3,4,6];[4]} are rows where these are present.
    ResultantArray{3,1} = {[1,2,4,6];[1,5,7,8];[1,8]}
  and so on for other elements of array1.

please help.

Answer 1

[Birdman]

for k=1:size(array1,1)
    for j=1:numel(array1{k,1})
        for i=1:size(array1,1)
            [~,idx(i,j,k)]=ismember(array1{k,1}(j),array1{i,1});
        end
        ResultantArray{k,j}=setdiff(find(idx(:,j,k)),k);
    end
end

[lucksBi]

Accurate. Thank You

Answer 2

[KSSV]

A for loop and ismember does the job......read about ismember

[lucksBi]

Yes i try this before posting question but i was doing some mistake with 3rd loop which @Birdman corrected accurately. Thank You