storing

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nitya ...
nitya ... 2011 年 3 月 22 日
for i=1:N-1
AF=AF+A(i)*2*cos((((2*(i-1))+1)/2)*w)
end
does N-1 values can be stored in the above code

回答 (2 件)

the cyclist
the cyclist 2011 年 3 月 22 日
AF = zeros(N-1,1);
for i=1:N-1
AF(i)=AF(i)+A(i)*2*cos((((2*(i-1))+1)/2)*w)
end
  2 件のコメント
the cyclist
the cyclist 2011 年 3 月 22 日
It is probably mostly a language barrier, but it is not clear what you want to do. Do you want to store all the cumulative sums, as you grow the values of AF? Then you could do what my code does (storing each intermediate value), then use the "cumsum" command to get the intermediate sums.
You need to write a longer, more detailed description of what you need, to get a good answer.

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Matt Fig
Matt Fig 2011 年 3 月 22 日
I would offer two criticisms of your code. First, you are using the built-in MATLAB variable i as a loop index. This will bite you later when you try to use it as the imaginary unit. Second, you should pre-allocate the variable AF instead of growing it in a loop:
AF = zeros(1,N-1) % Pre-allocation
for ii=1:N-1
AF(ii) = AF(ii) + A(ii)*2*cos((((2*(ii-1))+1)/2)*w);
end

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