Converting 27 bit signed binary to decimal
25 ビュー (過去 30 日間)
古いコメントを表示
I have a textfile with 1024 lines, each line containing a 27 bit signed binary number. I need to convert the data in this textfile to decimal. I know how to convert signed binary of length 16, but I'm not sure how to convert 27 bit since the function uint16 does not apply to 27 bit numbers. Does anyone know how to convert 27 bit signed binary numbers into decimal? Thank you very much
2 件のコメント
James Tursa
2018 年 1 月 5 日
What exactly is in the text file? Can you give a short example? Is it character data with '0' and '1', or something else?
回答 (1 件)
Walter Roberson
2018 年 1 月 5 日
Your input file does not have 27 bit signed binary numbers: it has 32 bit signed binary numbers. 22 bits of the range are significant, but because they are stored as 32 bit you can read them as 32 bit.
fid = fopen('output_real.txt', 'rt');
datacell = textscan(fid, '%s');
fclose(fid);
values = typecast(uint32(bin2dec(char(datacell{1}))),'int32');
2 件のコメント
Walter Roberson
2018 年 1 月 5 日
fid = fopen('output_really_real_not_that_fake_32bit_stuff.txt', 'rt');
datacell = textscan(fid, '%s');
fclose(fid);
temp = char(datacell{1}));
temp = [repmat(temp(:,1),1,5), temp]; %sign extend
values = typecast(uint32(bin2dec(temp)), 'int32');
参考
カテゴリ
Help Center および File Exchange で String Parsing についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!