how to sort in increasing order using loop?

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

6 件のコメント

David Goodmanson
David Goodmanson 2017 年 12 月 16 日
Hello baiti, what don't you like about this? It's a bubble sort in increasing order and it works.
baiti
baiti 2017 年 12 月 16 日
then, i think my matlab is the problem. i really dont have any idea why it wont work on my matlab. any suggestion?
David Goodmanson
David Goodmanson 2017 年 12 月 16 日
It's cleaner to put A = zeros(1,6) at the beginning, so that if you run the script more than once you get a fresh start for A. I put disp(A) at the end as well, so that you can see the results of your efforts.
Image Analyst
Image Analyst 2017 年 12 月 16 日
To format your code read this
Why don't you just use the built-in sort() function?
Jan
Jan 2017 年 12 月 17 日
@baiti: It seems like you have a problem running this code. Then it would be useful, if you mention what the problem is. "it wont work on my matlab" does not allow to reconsider, why you are not satisfied.
Manish Kumar
Manish Kumar 2020 年 6 月 26 日
Do you want better algorithm than this?

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回答 (1 件)

rohan hazarika
rohan hazarika 2020 年 9 月 18 日

0 投票

for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end

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質問済み:

2017 年 12 月 16 日

回答済み:

2020 年 9 月 18 日

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