how do you Calculate the amplitude of the signal for a period of 1 second

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Adrison Cardozo
Adrison Cardozo 2017 年 12 月 14 日
編集済み: Harish Ramachandran 2017 年 12 月 20 日
hi
  3 件のコメント
Adrison Cardozo
Adrison Cardozo 2017 年 12 月 14 日
The question goeslike this so i have to analyze the signal changes in time for that, write a script that calculates the maximum and minimum values of the signal.
The values are c=0 C1=0.1155 C2=0.3417 C3=0.1789 C4=0.1232 C5=0.0678 C6=0.0473 C7=0.0260 C8=0.0045 C9=0.0020
Adam
Adam 2017 年 12 月 14 日
And what is your problem with doing it? People aren't (usually) going to just do it for you without you showing any effort.

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回答 (1 件)

Harish Ramachandran
Harish Ramachandran 2017 年 12 月 20 日
編集済み: Harish Ramachandran 2017 年 12 月 20 日
This is a very trivial implementation of calculating max / min values of signal amplitude (sine in this case) at a particular time interval. This should be a good starting point to customize for your purpose.
step = 0.2; %step for time
ll = 0; %lower limit of time
ul = 5; %upper limit of time
t = ll:step:ul; %time function
f = sin(t); %sine function for reference - can be replaced with your equivalent
interval = 1; %get max and min at interval (default = 1)
x = 1:(interval/step):max(size(f)); %calculate the indices when the switch in indices to the next interval will happen
for i=1:1:max(size(x))-1 %loop through and obtain the mx and mn values
mx(i) = max(f(x(i):1:x(i+1)-1));
mn(i) = min(f(x(i):1:x(i+1)-1));
end
mx and mn contain the values of the maximum and minimum values at time (0:1:5)
Henceforth while posting a question, please provide details of the use case and your initial effort. Thank you.

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