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What can I write in a MATLAB function block in Simulink?

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Maria
Maria 2017 年 12 月 12 日
コメント済み: Birdman 2017 年 12 月 13 日
Hi I am working with Simulink. I wrote a function in Matlab that basically does a circular shift, and I wanted to put it into Simulink by using the MATLAB function block. The thing is that if I write
function y= shift_with0(u,s)
y = circshift(u,s);
y(1:s)=0;
end
no problem and everything is working. But, I wanted to allow as inputs also vectors, so I wrote this function
function y= shift_with0(u,s)
if isvector(s)
pm=sign(s);
inegatif = sum(pm(:)==-1);
s = inegatif;
end
y = circshift(u,s);
y(1:s)=0;
end
In Matlab is working, but the Simulink block not. So, I assume that is the "if" part that Simulink does not accept. In general, could someone clarify for me what I can write/not write in a MATLAB function block? Thanks
  4 件のコメント
Maria
Maria 2017 年 12 月 12 日
You are right about the isvector. I modified it
function y= shift_with0(u,s)
[n,m] = size(s);
if n>1 || m>1
pm=sign(s);
inegatif = sum(pm(:)==-1);
s = inegatif;
end
y = circshift(u,s);
y(1:s)=0;
end
With y(1:s)=0 I set the components before the "s" point to zero. It is because want to shift indeed, not really to circularly shift. I found this solution that suits me. In front of the values that have been shifted, I want zero. In Matlab I get what I actually want. But Simulink complains. I attach the file.

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採用された回答

Birdman
Birdman 2017 年 12 月 12 日
Run the attached model and let me know the results.
  16 件のコメント
Birdman
Birdman 2017 年 12 月 13 日
You are welcome, Maria.

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その他の回答 (1 件)

KL
KL 2017 年 12 月 12 日
If s is a vector, I will just count the number of negative entries, and then shift the y by this amount
Shouldn't you be simply writing,
...
if numel(s)>1
s = numel(s(s<0));
end
y = circshift(u,s);
...
  3 件のコメント
Maria
Maria 2017 年 12 月 12 日
Thanks!

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