Subscripted assignment dimension mismatch

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Mark Lupton
Mark Lupton 2012 年 5 月 3 日
I got an error saying "Subscripted assignment dimension mismatch"
I have this:
clc
clear all
global Mw M0 H rho g theta sigma dt A Rmax
Mw=0.001; M0=0.001; H=0.1; rho=200; g=10;
cos(theta)=0.1; sigma=0.03; dt=0.0004; A=0.00005;Rmax=0.001;
Vtotal=A*H;
for i=1:20
iter=1;
Vvoid=0;
porosity=0;
while porosity < 0.2
R(iter)=Rmax*rand(1);
Vvoid= Vvoid + pi*(R(iter)^2)*H;
porosity=Vvoid/Vtotal;
iter=iter+1;
end
Z=zeros(iter-1,2001);
for t=2:2001
sum=0; sum1=0;
for k=1:iter-1
[Z(k,t)]=Zcalculator(R(k),Z(k,t-1));
sum = sum + pi*(R(k)^2)*Z(k,t);
sum1 = sum1 + pi*(R(k)^2)*H;
end
recovery(i,t)=100*(sum/sum1);
end
end
&&&&&& and my error reads as follows::
??? Subscripted assignment dimension mismatch.
Error in ==> GroupProject at 29
[Z(k,t)]=Zcalculator(R(k),Z(k,t-1));
% does anyone know what is going on???
  1 件のコメント
Thomas
Thomas 2012 年 5 月 3 日
what is the function Zcalculator?

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回答 (1 件)

Geoff
Geoff 2012 年 5 月 3 日
Enter the command:
dbstop if error
Now run your script and wait for it to break.
Then, in the command window, execute the line:
Zcalculator(R(k),Z(k,t-1));
Is it a scalar? Probably not. You are assigning to Z(k,t), which expects a scalar (because you are asking MatLab to put a value into a single element of Z).
By the way, you don't need to put square brackets around Z(k,t) when you do the assignment.

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