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Star Strider
Star Strider 2017 年 12 月 11 日

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The optimisation routines need vector input for the parameters. I combine them as vector ‘p’ here.
Try this:
x0 = [0.5; 500];
[x, fval] = fmincon(@(p) -launch(p(1),p(2)), x0, [],[],[],[], [0.11 15], [1 1310])
Note that the optimisation functions minimise the function output, so to maximise it, you need to negate the the function.
When I ran your function, I got:
x =
893.8695e-003
473.4764e+000
fval =
-38.4141e+000
So ‘m2=0.89’, ‘k2=473’, producing a distance of 38.4.
You may need to experiment to get the result you want. See the documentation for fmincon for details on what it can do.

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Star Strider
Star Strider 2017 年 12 月 11 日
Walle Walhood’s Answer moved here —
So, the fval is a negative number.? is there a way to limit the output make sure it is a positive number?
Also, thank you very much for your help
Star Strider
Star Strider 2017 年 12 月 11 日
My pleasure.
Since I negated the function in order to maximise it, fval will be negative. Just remove the minus sign to get the correct result.
If my Answer helped you solve your problem, please Accept it!

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その他の回答 (1 件)

Walle Walhood
Walle Walhood 2017 年 12 月 11 日

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I sure will, Thanks again!

1 件のコメント

Star Strider
Star Strider 2017 年 12 月 11 日
As always, my pleasure!
Also, you can run your function with the optimised variables to get the ‘positive’ distance.

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