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Is constructor method the only method that creates an object in a class definition?

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Yves
Yves 2017 年 12 月 11 日
コメント済み: Yves 2017 年 12 月 11 日
Another way to ask this question is: how do I create a value class object as the output of a handle class ordinary method? For example,
classdef handleClassA < handle
properties
end
methods
function obj = handleClassA(varargin)
...
end
function ValueClassobj2 = unknownmethod(handleClassAobj, ValueClassobj1)
ValueClassobj2.property1 = ...
some_sort_function(handleClassAobj.property3, ValueClassobj1.property1);
...
end
end
end
If I do it the above way, the output is a struct with field property1, etc., not a object of a class.
  6 件のコメント
Steven Lord
Steven Lord 2017 年 12 月 11 日
digraph is the constructor for the digraph class included in MATLAB since release R2015b.
In this simple example createDigraph only calls the constructor for the digraph class with a sample matrix returned from the bucky function (also included in MATLAB.)
In a "real world" scenario the myHandleClass object would probably have properties that the createDigraph method would use to compute the matrix with which you call the digraph constructor.
Yves
Yves 2017 年 12 月 11 日
Thx, Steven.

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Matt J
Matt J 2017 年 12 月 11 日
編集済み: Matt J 2017 年 12 月 11 日
I think you are trying to do,
function ValueClassobj2 = unknownmethod(handleClassAobj, ValueClassobj1)
ValueClassobj2 = ValueClassobj1; %clone of obj1
ValueClassobj2.property1 = ...
some_sort_function(handleClassAobj.property3, ValueClassobj1.property1);
...
end
  1 件のコメント
Yves
Yves 2017 年 12 月 11 日
編集済み: Matt J 2017 年 12 月 11 日
Matt, if I understand you correctly, the statement
ValueClassobj2 = ValueClassobj1;
creates the object "ValueClassobj2", in the same class as "ValueClassobj1". Correct?
What if I don't have a same class object as "ValueClassobj2" that I wanted to create, but an array of input variables? Will I still be able to define "unknownmethod" as a method of currect class "handleClassAobj", to create the object "ValueClassobj2"?

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