In binary image, how to convert large black pixels area into white ?

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Y.L.K KHUMAN
Y.L.K KHUMAN 2017 年 12 月 7 日
コメント済み: Y.L.K KHUMAN 2017 年 12 月 9 日
I am working on skew detection and correction. I had corrected the skewness of the image, but I found that there is large size of Black areas on all sides of the corrected image. I tried to convert the black pixels (large area only) to white using the following codes. But it is not working properly. Sometimes its also remove black pixel from the pictures itself and sometimes it does not remove the larger area of the black pixels.
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measurements = regionprops(SkewCorrectedImage == 0, 'Area','PixelIdxList');
Regions = find([measurements.Area] >=200000);%%
theIndexes = vertcat(measurements(Regions).PixelIdxList);
c=SkewCorrectedImage;
(theIndexes)=1
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Jan
Jan 2017 年 12 月 7 日
You should be able to set the added pixels to white directly in the code for rotating the image. This would be much smarter that using an auto-detection of the black triangles afterwards. So please post the code to obtain the shown image.
Y.L.K KHUMAN
Y.L.K KHUMAN 2017 年 12 月 7 日
編集済み: Y.L.K KHUMAN 2017 年 12 月 7 日
Here is the rotation part code:
props = regionprops(joinedBlobs, 'BoundingBox','Orientation'); % Find bounding box.
boundingBox = props.BoundingBox;
angle = props.Orientation
angleToRotate = -angle(1);
figure, imshow(IPImg), rectangle('Position', boundingBox, 'EdgeColor', 'red');
croppedImage = imcrop(IPImg, props.BoundingBox);
figure, imshow(croppedImage), title('cropped Image');
SkewCorrectedImage = imrotate(croppedImage, angleToRotate);
figure, imshow(SkewCorrectedImage), title('corected image');
imsave();

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回答 (1 件)

Akira Agata
Akira Agata 2017 年 12 月 7 日
You can easily do that by using imclearborder function, like:
BWout = ~yourBinaryImage;
BWout = imclearborder(BWout);
BWout = ~BWout;
  1 件のコメント
Y.L.K KHUMAN
Y.L.K KHUMAN 2017 年 12 月 9 日

Thank for your help. When I try this code, it removes some boundary part, which is also a part of the image. Rotated Image:

After Using your code:

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