Indexing for cell arrays
1 回表示 (過去 30 日間)
古いコメントを表示
I have 10x1300 cell array z, how do i find a certain value of z using indexing
find(abs(z-z_position)<intvl) did not work
and how do i do the opposite as well? eg. z{1,1}(1)
A portion of z, z value is random for each cell.
Columns 1296 through 1300
[1×23 double] [1×23 double] [1×29 double] [1×23 double] [1×25 double]
[1×27 double] [1×25 double] [1×25 double] [1×25 double] [1×27 double]
[1×21 double] [1×25 double] [1×27 double] [1×27 double] [1×25 double]
[1×27 double] [1×29 double] [1×29 double] [1×25 double] [1×23 double]
[1×27 double] [1×25 double] [1×23 double] [1×27 double] [1×27 double]
[1×27 double] [1×27 double] [1×23 double] [1×21 double] [1×23 double]
[1×25 double] [1×29 double] [1×27 double] [1×27 double] [1×27 double]
[1×27 double] [1×21 double] [1×21 double] [1×29 double] [1×27 double]
[1×25 double] [1×25 double] [1×25 double] [1×21 double] [1×27 double]
[1×23 double] [1×25 double] [1×25 double] [1×25 double] [1×23 double]
0 件のコメント
採用された回答
Walter Roberson
2017 年 11 月 20 日
cellfun( @(Z) find(abs(Z-z_position)<intvl), z, 'uniform', 0)
the output will be a cell array each element of which is the list of indices for the corresponding cell in z.
9 件のコメント
Walter Roberson
2017 年 11 月 21 日
Do you need to know just the value out of all of the M, or do you need to know which cell of M it came from and the index inside that cell?
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Matrices and Arrays についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!