Replacing elements of a matrix
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Hello, I have a 15*15 matrix of all zeros.I want to replace each element of the matrix with different 2*2 matrices. How can it be done?
Thanks
2 件のコメント
Andrei Bobrov
2017 年 11 月 20 日
Do you want get a 30 x 30 matrix?
Santosh Nath
2017 年 11 月 20 日
yes. I think 30*30 matrix is the only possible option in this case
回答 (2 件)
Walter Roberson
2017 年 11 月 20 日
0 投票
That cannot be done. Numeric matrices must have scalars at each position.
It would be possible to convert the numeric matrix to a cell array and then replace the cell contents. num2cell() would do the conversion to cell.
2 件のコメント
Santosh Nath
2017 年 11 月 20 日
Thanks fore the ans. I shall try your suggestion.
Walter Roberson
2017 年 11 月 20 日
newMatrix = kron(YourMatrix, [1 1;1 1]);
newMatrix(I*2-1:I*2, J*2-1:J*2) = TwoByTwoMatrixFor(I,J)
Andrei Bobrov
2017 年 11 月 20 日
InitData = randi(150,2,2,15,15);
out = reshape(permute(InitData,[1 3 2 4]),30,[]);
or
InitData = arrayfun(@(x)randi(150,2,2),ones(15),'un',0);
out = cell2mat(InitData);
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