Subtract column vectors from eachother in every possible constelation
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I have a column matrix "Sample (10,n)" and now I want to subtract the column matrix "Testp (10,n)" from the Sample-matrix. To be more specific, I need to subtract the columns from eachother so that "(Sample(:,1) - TestP(:,1)) + (Sample(:,2) - TestP(:,2)) + ... " will be executed. But it has to be done for every constelation so that for n-th column every entry is taken, than the n-th-1 column switches to the second row-entry and from the n-th vector every value is taken and so on, that in the end I will get a column matrix "gamma (10,don't know".
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Guillaume
2017 年 11 月 13 日
So, does your C also include (b2-y1), (b2-y2), ..., (b3-y1), ... and for the 1st column (a1-x2), ... (a2-x1), ... ?
If so there shouldn't be any I don't know, the number of combinations is size(Sample, 1) ^ (2* size(Sample, 2))
For a 50x10 matrix, that is about 9.7e16 elements something that would require over 710,000 petabytes of memory. I doubt you have anywhere that amount of memory (or the time required to calculate that many elements), so you may want to rethink your problem.
回答 (1 件)
Jan
2017 年 11 月 13 日
With some guessing:
n = 7;
Sample = rand(10, n);
Testp = rand(10, n);
gamma = Sample - reshape(Testp, 10, 1, n); % >= R2016b: Auto-Expand
With older Matlab versions:
gamma = bsxfun(@minus, Sample, reshape(Testp, 10, 1, n));
Is this what you want? Perhaps a:
gamma = reshape(gamma, 10, []);
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