Sorry, the question is: why is my underfunction not remembering my earlier value of A1 and how can i make it to remember?
loop with easy underfunction
10 ビュー (過去 30 日間)
古いコメントを表示
function tretti
for k=1:3
F=results(k)
end
function h=results(k)
A ={k*2};
A1(k)= A
h=A1
%output: F=[] [] [6]
%what i want: F=[2] [4] [6] //cell array
回答 (1 件)
Rik
2017 年 11 月 7 日
Because you are overwriting it every iteration.
function F=tretti
for k=1:3
F{k}=results(k);
end
function h=results(k)
A ={k*2};
A1(k)= A;
h=A1;
You should look into cellfun, it may be really useful for what you are trying to do.
2 件のコメント
Rik
2017 年 11 月 7 日
The modification of your code should work. You could also generate it as a vector or matrix, and then convert it to a cell with num2cell (or mat2cell).
参考
カテゴリ
Help Center および File Exchange で Cell Arrays についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!