MATLAB Answers

dividing a table into an array of subtables

9 ビュー (過去 30 日間)
fima v
fima v 2017 年 11 月 7 日
コメント済み: Robert 2017 年 11 月 16 日
Hello i have an array which look like in the photo bellow. every contactID has one or many activities(which are listed on the next rows under an empty contact id).
for example in line 15's contact id we have one activity and the next activity is at line 16.
how can i make an array of "contact_id"'s and in every cell we will have a sub array which adds all the activities if the following empty "contact id cell" as one array for this contact id?
thanks
mark |

  0 件のコメント

サインインしてコメントする。

採用された回答

Robert
Robert 2017 年 11 月 7 日
In general, your task will be easier if you start by filling in those blank IDs. I will use data to refer to your table.
%%Fill in blanks (assumes first row is not blank)
for ii = 1:height(data)
ID = data.ContactID{ii};
if ~isempty(ID) % First occurance
prev = ID;
else % Not first occurance
data.ContactID{ii} = prev;
end
end
Then you can gather the IDs and select table subsets by common ID
[ID, ~, index] = unique(data.ContactID);
grouped = table();
grouped.ContactID = ID;
grouped.ActivityData = cell(height(grouped), 1);
for ii = 1:length(ID)
grouped.ActivityData{ii} = data(index == ii, 2:end);
end
You could also do this in a containers.Map object instead of a table.
grouped = containers.Map();
for ID = unique(data.ContactID)'
grouped(ID{1}) = data(strcmp(data.ContactID, ID{1}), 2:end);
end

  5 件のコメント

表示 2 件の古いコメント
Robert
Robert 2017 年 11 月 7 日
@Guillaume
Thanks for mentioning fillmissing; very cool! I am using R2016a most of the time, which is one release too old for fillmissing.
fima v
fima v 2017 年 11 月 7 日
Hello ,how its possible keep only the latest activity which has the highest date among them , for each contact ?
Thanks
Robert
Robert 2017 年 11 月 16 日
You should take a look at the second output of unique . It gives you the index of the first occurrence of each unique value. Specify that you want the 'last' occurrence and or sort your data by date as needed.

サインインしてコメントする。

その他の回答 (0 件)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by