date time convert to elapsed time
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I have a vector of date times in 'HH:MM:SS' format which I want to convert to elapsed time. Each cell is a 1 minute increment from the previous.
Right now I'm doing a for loop that loops the size of the entire vector, and does x(i)-x(1) to calculate the elapsed time (in minutes).
This seems kind of cumbersome code, and I feel like there's an easier way. Any recommendations?
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採用された回答
Thomas
2012 年 4 月 25 日
your cell array
c={'12:00:00' '12:00:01' '12:00:02' '12:00:03'}
d=datenum(c,'HH:MM:SS')
out=d-d(1);
time_sec=out*86400
その他の回答 (1 件)
Walter Roberson
2012 年 4 月 25 日
datenum() the cell array of date strings to get out a vector of serial date numbers. Subtract the first value from the array to get the elapsed times in days. Multiply by 24*60 to get elapsed times in minutes. No loop should be needed.
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