Function Output Not Displaying Why??

function PT=myPascal(n)
PT=zeros(n,n);
for i=1:n
    for j=1:i
        if n>0
        PT(i,j)=factorial(i-1)/(factorial(j-1)*factorial(i-j));
        else fprintf ('Error: The input argument is not a positive integer >0')
        end
    end
end

>> myPascal(5)

ans =

       1     0     0     0     0
       1     1     0     0     0
       1     2     1     0     0
       1     3     3     1     0
       1     4     6     4     1

>> myPascal(-1)

ans =

       []

Answer 1

[Walter Roberson]

You have

 for i=1:n
    for j=1:i
        if n>0

The "for i" loop will not have its body executed unless 1:n is non-empty, which requires that n be at least 1. Therefor the test "if n>0" will never be reached unless n is at least 1, so "if n>0" can never be true in that code.

[Kim Hao Teong]

im confused in which part of the code i have defined something = 0?

[Walter Roberson]

Correction: n>0 can never be false for that code.

Your code has PT=zeros(n,n) which sets PT to zero.

You should correct your code to

if n < 1
  fprintf ('Error: The input argument is not a positive integer')
else
  for i=1:n
    for j=1:i
        PT(i,j)=factorial(i-1)/(factorial(j-1)*factorial(i-j));
    end
  end
end