Find cell array and replace with another cell array in main cell array?
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I have 3 cell arrays. A={true;true;true;false;false;true;true;true;false;true;true;true;false;false;false}; How can I find B={true,true,true}; in A
and how can I replace that founded part with C={K;L;M};??
2 件のコメント
Cam Salzberger
2017 年 11 月 3 日
Can I ask why you are using a cell array? Are K, L, and M all logical values as well?
If that's the case, generally a logical array would be more memory-efficient, parsing time-efficient, and allow for simpler code.
採用された回答
Chenchal
2017 年 11 月 3 日
編集済み: Chenchal
2017 年 11 月 3 日
Not efficient -- see below...
% code
A = {true;true;true;false;false;true;true;true;false;true;true;true;false;false;false};%logical row vector
B = {true,true,true};%logical col vector
C = {false,false,false};% assumption: replacement must also be logical col vector
% Convert all to strings, use regexprep, convert back
Rchar = regexprep(num2str(cell2mat(A))',num2str(cell2mat(B)')',num2str(cell2mat(C)')');
% Have to use _arrayfun_ since the output type must also be a cell array
R = arrayfun(@(x) {logical(x)},str2num(char(split(Rchar,''))))';
based in Guillaume comment:
% code
A = {true;true;true;false;false;true;true;true;false;true;true;true;false;false;false};%logical row vector
B = {true,true,true};%logical col vector
C = {false,false,false};% assumption: replacement must also be logical col vector
R = logical(strrep(cell2mat(A'),cell2mat(B),cell2mat(C)))
%need to convert logical array to cell array ??
Based on Cam comment:
%code
Rchar2 = regexprep(char(cell2mat(A)+'0')',char(cell2mat(B)+'0'),char(cell2mat(C)+'0'));
R2 = arrayfun(@(x) {logical(x)},str2num(char(split(Rchar2,''))))';
3 件のコメント
Cedric
2017 年 11 月 3 日
Careful, STRREP and REGEXPREP are not working the same way. Regexp engines "eat" the string, STRREP does not:
>> strrep( 'aaa', 'aa', 'bb' )
ans =
'bbbb'
>> regexprep( 'aaa', 'aa', 'bb' )
ans =
'bba'
and STRFIND operates like STRREP:
>> strfind( [true,true,true], [true,true] )
ans =
1 2
その他の回答 (1 件)
Cam Salzberger
2017 年 11 月 3 日
Ali,
Regardless of your reason for using cell arrays initially, it is likely to be faster to convert them to logical arrays before searching for the pattern. Chenchal shows you how to do that with cell2mat.
However, I would not recommend converting the logical values into character representations of their values (i.e. converting true into '1' and false into '0'). The conversion from number to character and back takes significant time that is likely to be unnecessary.
Once you have your logical arrays, you can use any of the algorithms mentioned in this blog post to find the location of the patterns, and then replace them with simple indexing and assignment.
If you would like to use any string-search functionality, rather than using num2str, I'd recommend just converting the logical values directly to some character values. It doesn't really matter which character value it is, so long as you can do matching with it. For easy of examination though, you could just do this:
charArray = char(logicalArray+'0');
Hope this helps!
-Cam
3 件のコメント
Chenchal
2017 年 11 月 3 日
Hey thank you Guillaume, I did not realize that! So below should do:
% code
A = {true;true;true;false;false;true;true;true;false;true;true;true;false;false;false};%logical row vector
B = {true,true,true};%logical col vector
C = {false,false,false};% assumption: replacement must also be logical col vector
R = logical(strrep(cell2mat(A'),cell2mat(B),cell2mat(C)))
R is a logical array, how to convert to cell array?
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