How do I store data in multiple loops?

1 回表示 (過去 30 日間)
Scott Powers
Scott Powers 2017 年 11 月 2 日
回答済み: Roman Müller-Hainbach 2017 年 11 月 2 日
So I have the task to solve a system of equations over a range of temperatures and a range of volumes. From this, I am supposed to make surface plots of my results. The problem is, I can only get one of my loops to output it's proper range of data, because I do not know how to get matlab to store the data from the loops in a matrix, instead of creating one long vector. If anyone could help, that would be wonderful. Thanks
%this first section is just constants the equations need to run
mdot=1; %L/min
A=2; %2mol/L concen A
E=1; %mol/L concen Enzyme
%therefore molar flow rate is 2 mol/min in and out
ndot=2;
%knb=kb-1, ktb=kb2
kb=0.4;
knb=0.03;
ktb=0.005;
kc=0.05;
knc=0.045;
ktc=0.03;
KMB=(knb+ktb)/kb;
KMC=(knc+ktc)/kc;
v=20;
x1=[];
x2=[];
x3=[];
x4=[]; %this is just to check the total mol balance
%Out of the cstr
x5=[];
xa=[];
xb=[];
xc=[];
xd=[];
xf=[];
xg=[];
xUU=[];
%VCSTR 20->500 L
DH1=9000; %in J/mol
DG1=-10000;
DH2=-15000;
DG2=500;
DH3=30000;
DG3=500;
P=0.5;
R=8.314;
spaces=24;
n=((500-20)/spaces)+1;
J=linspace(20,500,n);
T=273
%so here is the problem. I need to run temperature from 273 to 423.
%However when I try to loop temperatures, it spits out all of my x values linearly instead of in a grid.
for i=1:1
Lk1=(-1/R)*(((DG1-DH1)/298)+(DH1/T));
k1=exp(Lk1)
Lk2=(-1/R)*(((DG2-DH2)/298)+(DH2/T));
k2=exp(Lk2)
Lk3=(-1/R)*(((DG3-DH3)/298)+(DH3/T));
k3=exp(Lk3)
%y(1)=a y(2)=b y(3)=c y(4)=d y(5)=f y(6)=G y(7)=Z1 y(8)=Z2 y(9)=Z3
for w=1:length(J)
fun=@(x)ndot-x-(ktb*E*x/(x+KMB*mdot))*v-(ktc*E*x/(x+KMC*mdot))*v;
x0=1;
[x]=fsolve(fun,x0); %A
v=v+spaces;
xtwo=(ktb*E*x/(x+KMB*mdot))*v; %B
xthree=(ktc*E*x/(x+KMC*mdot))*v; %C
xfour=[x]+xtwo+xthree; %Checks that CSTR moles stay the same
Eqsys=@(y)[(k1*(y(1)^2)*y(2)*y(3))-((y(4)^3)),
(k2*y(1)*y(2))-(y(3)*(y(5)^3)*(P^2)),
(k3*P*y(1)*y(2))-y(6),
([x]-2*y(7)-y(8)-y(9)-y(1)),
(xtwo-y(7)-y(8)-y(2)),
(xthree-y(7)+y(8)-y(9)-y(3)),
((3*y(7))-y(4)),
((3*y(8))-y(5)),
(y(9)-y(6))];
b=[1,1,1,1,1,1,1,1,1];
q=fsolve(Eqsys,b);
x1=[x1;[x]]; %A range of vol
x2=[x2 xtwo]; %B ''
x3=[x3 xthree]; %c"
x4=[x4 xfour];
x5=[x5;q];
xa=[xa;q(:,1)];
xb=[xb;q(:,2)];
xc=[xc;q(:,3)];
xd=[xd;q(:,4)];
xf=[xf;q(:,5)];
xg=[xg;q(:,6)];
end
T=T+(150/(n));
end
% so if anyone can get the values to run from v=20 to 500 and T=273 to 423, that would be wonderful. Thanks
  2 件のコメント
KSSV
KSSV 2017 年 11 月 2 日
Your code is pretty messy....you have to tell what you are trying to solve....or give the complete code which tried and your expectations.
Scott Powers
Scott Powers 2017 年 11 月 2 日
I am trying to solve y(1) through y(9) for all volumes v=20 to v=500 with a temperature range of 273-423. This should be able to give me a surface plot of all of the values of y(1) (or the other variables) at all the temps and volumes. Basically it should be a 3D plot of the solved variables against the volumes and temps.

サインインしてコメントする。

回答 (1 件)

Roman Müller-Hainbach
Roman Müller-Hainbach 2017 年 11 月 2 日
Try concatenating the column vectors in the first dimension. Use [x,y] instead of [x;y] or use horzcat(x,y). This only works of course if the vectors you want to arrange in a matrix always have the same length.

カテゴリ

Help Center および File ExchangeSurface and Mesh Plots についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by