# Split array into cell arrays of different size

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lightroman 2017 年 11 月 1 日

I have an array that I am trying to divide into different lengths arrays. The array is 750000 values or so long so I needed an efficient way. I want to start the next array when pattern finishes or begins to start over.
An example would be
A = [5 19 43 28 5 19 43 5 19 43 28 5 19 5 19 43]
I want the result to be something like
Result = {5 19 43 28} {5 19 43} {5 19 43 28} {5 19} {5 19 43}
However, it can also be a longer pattern, [5 19] is how I know the pattern restarts because these values only occur at the beginning of each data set.

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### 回答 (1 件)

Cedric Wannaz 2017 年 11 月 1 日
>> seqs = mat2cell( A, 1, diff( [strfind(A, [5,19]), numel(A)+1] ))
seqs =
1×5 cell array
{1×4 double} {1×3 double} {1×4 double} {1×2 double} {1×3 double}
##### 2 件のコメント表示非表示 1 件の古いコメント
Cedric Wannaz 2017 年 11 月 2 日
Which version of MATLAB are you using? STRFIND has been working with numeric array for a long time.
seqs = mat2cell( A, 1, diff( [find(A(1:end-1)==5 & A(2:end)==19), numel(A)+1] ))
and if you need to be more flexible about the size of start patterns, we can generalize the call to FIND, but for this I'll need to know your version of MATLAB.

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