Split array into cell arrays of different size
4 ビュー (過去 30 日間)
古いコメントを表示
I have an array that I am trying to divide into different lengths arrays. The array is 750000 values or so long so I needed an efficient way. I want to start the next array when pattern finishes or begins to start over.
An example would be
A = [5 19 43 28 5 19 43 5 19 43 28 5 19 5 19 43]
I want the result to be something like
Result = {5 19 43 28} {5 19 43} {5 19 43 28} {5 19} {5 19 43}
However, it can also be a longer pattern, [5 19] is how I know the pattern restarts because these values only occur at the beginning of each data set.
0 件のコメント
回答 (1 件)
Cedric
2017 年 11 月 1 日
>> seqs = mat2cell( A, 1, diff( [strfind(A, [5,19]), numel(A)+1] ))
seqs =
1×5 cell array
{1×4 double} {1×3 double} {1×4 double} {1×2 double} {1×3 double}
2 件のコメント
Cedric
2017 年 11 月 2 日
編集済み: Cedric
2017 年 11 月 2 日
Which version of MATLAB are you using? STRFIND has been working with numeric array for a long time.
seqs = mat2cell( A, 1, diff( [find(A(1:end-1)==5 & A(2:end)==19), numel(A)+1] ))
and if you need to be more flexible about the size of start patterns, we can generalize the call to FIND, but for this I'll need to know your version of MATLAB.
参考
カテゴリ
Help Center および File Exchange で Matrices and Arrays についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!