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Compute double sum or double integral throug sum

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F.O
F.O 2017 年 10 月 30 日
回答済み: Roger Stafford 2017 年 10 月 30 日
x=[-20:0.2:10];
y=[-10:0.2:5];
u2=-3*exp(-sqrt(x.^2+y.^2)/2)
I want to sum this function from y=1 to the number of elements of y vector then the sum of this result from x=1 to the number of elements in x. IT is actually a double integral in form of sum.
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Adam
Adam 2017 年 10 月 30 日
You want to sum from y = 1 up to the number of elements in y even though y begins at -10 and runs to 5? How is that expected to work exactly?
F.O
F.O 2017 年 10 月 30 日
編集済み: F.O 2017 年 10 月 30 日
Here we are dealing with the position of the elements not the elements themseves. Maybe to use for loop command here. IT is actually a double integral which I should integrate with respect to from y= -10to y=5in the first step then with respect to x from x=-20 to x=10 I have dx=0.2 dy=0.2

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Honglei Chen
Honglei Chen 2017 年 10 月 30 日
If the ultimate goal is to compute the integral, you can consider using integral2
If you have to do it with sum, then since you already computed u2 for all values, it is just
x=[-20:0.2:10]; y=[-10:0.2:5]'; u2=-3*exp(-sqrt(x.^2+y.^2)/2);
sum(u2(:))*0.2*0.2
Note that you have to transpose x or y so it forms a grid
HTH
  2 件のコメント
F.O
F.O 2017 年 10 月 30 日
Could you explain more why we should use transpose here and what this the sum here works?
Guillaume
Guillaume 2017 年 10 月 30 日

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その他の回答 (1 件)

Roger Stafford
Roger Stafford 2017 年 10 月 30 日
[X,Y] = meshgrid(x,y);
M = -3*exp(-sqrt(X.^2+Y.^2)/2);
S = sum(M(:))*.2*.2; % The desired sum

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