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how can i solve problem in my code for adaptive median filter

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Daleel Ahmed
Daleel Ahmed 2017 年 10 月 28 日
回答済み: Zeeshan Salam 2019 年 3 月 24 日
function f= dd(r,Smax)
if (Smax <= 1) | (Smax/2 == round(Smax/2)) | (Smax ~= round(Smax))
error('SMAX must be an odd integer > 1.')
end
[M, N] = size(r);
% Initial setup.
f = r;
f(:) = 0;
alreadyProcessed = false(size(r));
%Begin filtering.
for k = 3:2:Smax
zmin = ordfilt2(r, 1, ones(k, k), 'symmetric');
zmax = ordfilt2(r, k * k, ones(k, k), 'symmetric');
zmed = medfilt2(r, [k k], 'symmetric');
processUsingLevelB = (zmed > zmin) & (zmax > zmed) & ...
~alreadyProcessed;
zB = (r > zmin) & (zmax > r);
outputZxy = processUsingLevelB & zB;
outputZmed = processUsingLevelB & ~zB;
f(outputZxy) = r(outputZxy);
f(outputZmed) = zmed(outputZmed);
alreadyProcessed = alreadyProcessed | processUsingLevelB;
if all(alreadyProcessed(:))
break;
end
end
% Output zmed for any remaining unprocessed pixels. Note that this
% zmed was computed using a window of size Smax-by-Smax, which is
% the final value of k in the loop.
f(~alreadyProcessed) = zmed(~alreadyProcessed);
  1 件のコメント
Daleel Ahmed
Daleel Ahmed 2017 年 10 月 28 日
編集済み: Walter Roberson 2017 年 10 月 28 日
Error using ordfilt2
Expected input number 1, A, to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64, logical
Instead its type was char.

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採用された回答

Walter Roberson
Walter Roberson 2017 年 10 月 28 日
You appear to be attempting to pass in characters for the first input to your function, the one named "r" here. That input must be numeric for this code to work.

その他の回答 (1 件)

Zeeshan Salam
Zeeshan Salam 2019 年 3 月 24 日
can u send me working of this algorithm and flowchart

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