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John
0

Text Extraction and retrieval

John
さんによって質問されました 2017 年 10 月 24 日
最新アクティビティ Cedric Wannaz
さんによって 編集されました 2017 年 11 月 9 日
<P ID=1>
A LITTLE BLACK BIRD.
</P>
<P ID=2>
Story about a bird,
(1811)
</P>
<P ID=3>
Part 1.
</P>
As I am new to text extraction, I need help in;
  1. Writing a code to count the delimiters (</P>)
  2. Remove all punctuation
  3. Break the text into individual documents at each delimiter, knowing that ID=1 refers to document 1, ID=2 refers to document 2. etc

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3 件の回答

Akira Agata
回答者: Akira Agata
2017 年 10 月 25 日
 採用された回答

Just tried to make a script to do that. Here is the result (assuming the maximum ID = 10).
% Read your text file
fid = fopen('yourText.txt');
C = textscan(fid,'%s','TextType','string','Delimiter','\n','EndOfLine','\r\n');
C = C{1};
fclose(fid);
% 1. Count the delimiters '</P>'
idx = strfind(C,'</P>');
n = nnz(cellfun(@(x) ~isempty(x), idx));
% 2. Remove all punctuation
C2 = regexprep(C,'[.,!?:;]','');
% 3. Break the text into individual documents at each delimiter
idx2 = find(strcmp(C,'</P>'));
for kk = 1:10
str = ['<P ID=',num2str(kk),'>'];
idx_s = find(strcmp(C,str));
if ~isempty(idx_s)
idx_e = idx2(find(idx2>idx_s,1));
fileName = ['document',num2str(kk),'.txt'];
fid = fopen(fileName,'w');
fprintf(fid,'%s\r\n',C(idx_s:idx_e));
fclose(fid);
end
end

  6 件のコメント

John
2017 年 10 月 28 日
You clearly understand 1 and 2, and a part of 3. For number 3, because ID=1 means Document 1, ID=2 means Document 2 etc. I want to also count the number of documents each word appear in.
Akira Agata
2017 年 10 月 30 日
Thanks for your reply. I've just made a script to do the items 1~3, as follows. I hope this will help you somehow.
Regarding your last question ("count the number of documents each word appear in"), I think you can do that by combining the following script with my previous one.
% Read your text file
fid = fopen('yourText.txt');
C = textscan(fid,'%s','TextType','string','Delimiter','\n','EndOfLine','\r\n');
C = C{1};
fclose(fid);
C = regexprep(C,'<[\w \=\/]+>',''); % Remove tags
C = regexprep(C,'[.,!?:;()]',''); % Remove punctuation and brackets
C = regexprep(C,'[0-9]+',''); % Remove numbers
C = lower(C); % Convert to lower case
% Extract every words
words = regexp(C,'[a-z\-]+','match');
words = [words{:}];
% (1) Count total number of words
numOfWords = numel(words); % --> 9
% (2) Count the total number of distinct words
numOfDistWords = numel(unique(words)); % --> 7
% (3) Find the number of times each word is used in the original text
wordList = unique(words);
wordCount = arrayfun(@(x) nnz(strcmp(x,words)), wordList);
% Show the result
figure
bar(wordCount)
xticklabels(wordList)
John
2017 年 11 月 7 日
Thanks. I am stuck running the counter.
for kk = 1:n
str = ['<p id=',num2str(kk),'>'];
idx_s = find(strcmp(C,str));
if ~isempty(idx_s)
idx_e = idx2(find(idx2>idx_s,1));
Doc=C(idx_s:idx_e); %May need to remove tags later
Doc = regexp(Doc,'[a-z0-9\-]+','match');
Doc = [Doc{:}];
Unique_Doc_count = arrayfun(@(x) nnz(strcmp(x,Doc)), Unique);
Unique_Doc_freq=[Unique;Unique_Doc_count];
end
end
I want to search if the elements in string array 'Unique' exist in 'Doc'. I got results in 'Unique_Doc_count' as the number of their occurrences but I need just 1 or 0 values (exist) or (not exist). The aim is to loop 'kk' over multiple documents and find the number of documents that contain each word in 'Unique'. Not even number of times the word occurs, but number of documents it appears in.

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Cedric Wannaz
回答者: Cedric Wannaz
2017 年 10 月 26 日

Here is another approach based on pattern matching:
>> data = regexp(fileread('data.txt'), '(?<=<P[^>]+>\s*)[\w ]+', 'match' )
data =
1×3 cell array
{'A LITTLE BLACK BIRD'} {'Story about a bird'} {'Part 1'}
if you don't need the IDs (e.g. if in any case they will go from 1 to the number of P tags), you are done.
If you needed the IDs, you could get both IDs and content as follows:
>> data = regexp(fileread('data.txt'), '<P ID=(\d+)>\s*([\w ]+)', 'tokens' ) ;
data = vertcat( data{:} ) ;
ids = str2double( data(:,1) )
data = data(:,2)
ids =
1
2
3
data =
3×1 cell array
{'A LITTLE BLACK BIRD'}
{'Story about a bird' }
{'Part 1' }

  6 件のコメント

Cedric Wannaz
2017 年 10 月 31 日
My pleasure!
John
2017 年 11 月 7 日
Thanks. I am stuck running a counter.
for kk = 1:n
str = ['<p id=',num2str(kk),'>'];
idx_s = find(strcmp(C,str));
if ~isempty(idx_s)
idx_e = idx2(find(idx2>idx_s,1));
Doc=C(idx_s:idx_e); %May need to remove tags later
Doc = regexp(Doc,'[a-z0-9\-]+','match');
Doc = [Doc{:}];
Unique_Doc_count = arrayfun(@(x) nnz(strcmp(x,Doc)), Unique);
Unique_Doc_freq=[Unique;Unique_Doc_count];
end
end
I want to search if the elements in string array 'Unique' exist in 'Doc'. I got results in 'Unique_Doc_count' as the number of their occurrences but I need just 1 or 0 values (exist) or (not exist). The aim is to loop 'kk' over multiple documents and find the number of documents that contain each word in 'Unique'. Not even number of times the word occurs, but number of documents it appears in.
Cedric Wannaz
2017 年 11 月 9 日
If you have a count per document, finding the number of documents a keyword is in is easy:
counts = [7, 0 ,3] ;
hasKey = counts > 0 ; % [1,0,1]
nDocs = sum( hasKey ) ; % 2

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回答者: Christopher Creutzig 2017 年 11 月 2 日
編集済み: Christopher Creutzig 2017 年 11 月 2 日

It's probably easiest to split the text and then check the number of splits created to count, using string functions:
str = extractFileText('file.txt');
paras = split(str,"</P>");
paras(end) = []; % the split left an empty last entry
paras = extractAfter(paras,">") % Drop the "<P ID=n>" from the beginning
Then, numel(paras) will give you the number of </P>.
If you do not have extractFileText, calling string(fileread('file.txt')) should work just fine, too.
In one of the comments, you indicated you also need to count the frequency of words in documents. That is what bagOfWords is for:
tdoc = tokenizedDocument(lower(paras));
bag = bagOfWords(tdoc)
bag =
bagOfWords with 13 words and 3 documents:
a little black bird .
1 1 1 1 1
1 0 0 1 0

  1 件のコメント

John
2017 年 11 月 7 日
Thanks. I am stuck running a counter.
for kk = 1:n
str = ['<p id=',num2str(kk),'>'];
idx_s = find(strcmp(C,str));
if ~isempty(idx_s)
idx_e = idx2(find(idx2>idx_s,1));
Doc=C(idx_s:idx_e); %May need to remove tags later
Doc = regexp(Doc,'[a-z0-9\-]+','match');
Doc = [Doc{:}];
Unique_Doc_count = arrayfun(@(x) nnz(strcmp(x,Doc)), Unique);
Unique_Doc_freq=[Unique;Unique_Doc_count];
end
end
I want to search if the elements in string array 'Unique' exist in 'Doc'. I got results in 'Unique_Doc_count' as the number of their occurrences but I need just 1 or 0 values (exist) or (not exist). The aim is to loop 'kk' over multiple documents and find the number of documents that contain each word in 'Unique'. Not even number of times the word occurs, but number of documents it appears in.

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