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My matlab code is giving me this error "Too many outputs requested". If someone can help me solve this?

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Brian Kim
Brian Kim 2017 年 10 月 17 日
回答済み: Stephen23 2017 年 10 月 17 日
My code is as follows:
function nn_ewn=optim_ewn(c_ewn)
case_ewn=case_one_ewn_gen(c_ewn);
a_cost=[];
for ii=1:1:size(case_ewn,2)
tmp_ewn=case_ewn{ii};
[t_cost t_Ic t_current t_a2]=find_cost(tmp_ewn);
u=fitdist(t_Ic,'normal');
wu=u.sigma; wn=u.mu;
u_arr=[]; cost_arr=[]; count=1;
while 1
ste=sum(tmp_ewn);
tmp2_ewn=tmp_ewn;
Hy=t_Ic-wn;
v1=max(Hy); v1_pos=find(Hy==v1);
v2=min(Hy); v2_pos=find(Hy==v2);
v4_pos=find(t_Ic==max(t_Ic));
v5_pos=find(t_Ic==min(t_Ic));
Ht=sort(t_Ic(:));
v6_pos=find(t_Ic==Ht(2));
d=1;
tmp3_ewn=tmp2_ewn;
if (tmp2_ewn(v1_pos) == 4 && tmp2_ewn(v2_pos) == 4) || (tmp2_ewn(v1_pos) == 12 && tmp2_ewn(v2_pos) == 12)
if (tmp2_ewn(v5_pos) == 4 && tmp2_ewn(v6_pos) == 4) || (tmp2_ewn(v5_pos) == 12 && tmp2_ewn(v6_pos) == 12)
tmp3_ewn=tmp2_ewn;
break
elseif (tmp2_ewn(v5_pos) == 4 && tmp2_ewn(v6_pos) ~= 4) || (tmp2_ewn(v5_pos) ~= 12 && tmp2_ewn(v6_pos) == 12)
tmp3_ewn(v5_pos)=tmp2_ewn(v5_pos)+d;
tmp3_ewn(v6_pos)=tmp2_ewn(v6_pos)-d;
elseif (tmp2_ewn(v5_pos) ~= 4 && tmp2_ewn(v6_pos) == 4) || (tmp2_ewn(v5_pos) == 12 && tmp2_ewn(v6_pos) ~= 12)
tmp3_ewn(v5_pos)=tmp2_ewn(v5_pos)-d;
tmp3_ewn(v6_pos)=tmp2_ewn(v6_pos)+d;
end
elseif (tmp2_ewn(v1_pos) == 4 && tmp2_ewn(v2_pos) ~= 4) || ...
(tmp2_ewn(v1_pos) ~= 4 && tmp2_ewn(v2_pos) == 4) || (tmp2_ewn(v1_pos) ~= 4 && tmp2_ewn(v2_pos) ~= 4) || ...
(tmp2_ewn(v1_pos) == 12 && tmp2_ewn(v2_pos) ~= 12) || ...
(tmp2_ewn(v1_pos) ~= 12 && tmp2_ewn(v2_pos) == 12) || (tmp2_ewn(v1_pos) ~= 12 && tmp2_ewn(v2_pos) ~= 12)
if (min(tmp2_ewn) >= 4 || max(tmp2_ewn) <= 12) && ...
(tmp2_ewn(v4_pos) >= 4 || tmp2_ewn(v5_pos) <= 12)
tmp3_ewn(v1_pos)=tmp2_ewn(v1_pos)-d;
tmp3_ewn(v2_pos)=tmp2_ewn(v2_pos)+d;
if tmp3_ewn(v1_pos) < 4 || tmp3_ewn(v2_pos) > 12
for jj=1:1:length(t_Ic)
v3_pos=find(t_Ic==Ht(jj)); % v3_pos is second minimum
if (tmp2_ewn(v3_pos) == 4) || (tmp2_ewn(v3_pos) == 12) %R
tmp_ewn=tmp2_ewn;
continue
elseif (tmp2_ewn(v3_pos) ~= 4 && tmp2_ewn(v3_pos) >= 4)|| (tmp2_ewn(v3_pos) ~= 12 && tmp2_ewn(v3_pos) <= 12)
tmp3_ewn(v3_pos)=tmp2_ewn(v3_pos)+d;
% tmp3_ewn(v3_pos)=tmp2_ewn(v3_pos)-d;
tmp3_ewn(v4_pos)=tmp2_ewn(v4_pos)-d;
break
end
end
end
end
end
if min(tmp3_ewn) < 4
n=length(tmp3_ewn);
tmp3_ewn(v4_pos)=4;
tmp3_ewn(n)=ste-sum(tmp3_ewn(1:end-1));
end
if max(tmp3_ewn) > 12
n=length(tmp3_ewn);
tmp3_ewn(v5_pos)=12;
tmp3_ewn(n)=ste-sum(tmp3_ewn(1:end-1));
end
tmp3_ewn
[g_cost g_Ic g_current g_a2]=find_cost(tmp3_ewn);
u1=fitdist(g_Ic,'normal');
if wu > u1.sigma
wu=u1.sigma
tmp_ewn=tmp3_ewn;
u_arr(count)=u1.sigma
cost_arr(count)=g_cost
g_Ic_cell{count}=g_Ic;
tmpe_cell{count}=tmp3_ewn';
cost_arr
count=count+1;
continue
elseif wu < u1.sigma
u_m_pos=find(u_arr == min(u_arr));
gt_ewn=tmpe_cell{u_m_pos};
gt_cost=cost_arr(u_m_pos);
gt_Ic=g_Ic_cell{u_m_pos};
break
end end
a_cost=[a_cost,gt_cost];
Ic_cell{ii}=gt_Ic;
n_ewn{ii}=gt_ewn;
end
n=length(n_ewn)
a_cost
mp_pos=find(a_cost==min(a_cost));
nn_ewn=n_ewn{mp_pos};
Error is..:
Too many outputs requested. Most likely cause is missing [] around
left hand side that has a comma separated list expansion.
Error in optim_ewn (line 98)
gt_ewn=tmpe_cell{u_m_pos};
Can someone help me solve this problem. Thank you.

回答 (2 件)

Jan
Jan 2017 年 10 月 17 日
u_m_pos=find(u_arr == min(u_arr));
gt_ewn=tmpe_cell{u_m_pos};
The message appears, if the minimal value min(u_arr) appears more than once inside u_arr.
If you want the index of one minimum only:
[~, u_m_pos] = min(u_arr);

Stephen23
Stephen23 2017 年 10 月 17 日
There is nothing preventing you from having zero, one, or more values returned. You need to take into account those situations. One solution is to simply return a subset of the cell array:
gt_ewn = tmpe_cell(u_m_pos);
Read more about cell array indexing here:

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