How to remove a part of string from a string. not manually.

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vijay chandra
vijay chandra 2017 年 10 月 10 日
コメント済み: Image Analyst 2017 年 10 月 11 日

Pdus_ENGINE_PKG_ENGINE_CPC_ENGINE_COM01_Container_ST3

I need Pdus only. I want to remove remaining part which is inside braces from the above string.i dont want to remove it manually by considering the remaining part.i need it in some other way.

(_ENGINE_PKG_ENGINE_CPC_ENGINE_COM01_Container_ST3).

回答 (1 件)

Image Analyst
Image Analyst 2017 年 10 月 10 日
Here's one way:
str = str(1:4); % Extract only the first 4 characters.
If that doesn't do it, then say why not.
By the way, the "above string" doesn't have braces in it.
  2 件のコメント
vijay chandra
vijay chandra 2017 年 10 月 11 日
I mentioned braces below. but the total string is above one. ok thank you.
Image Analyst
Image Analyst 2017 年 10 月 11 日
You can get rid of braces first like this
str = strrep(str, '{', '');
str = strrep(str, '}', '');
str = str(1:4); % Extract only the first 4 characters.

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