Can some one help me with this?

I have an array of character

arr = 'cat;tom;jerry;dog;cat'

and i also have a list of word need to search

wordSearch = 'tom,cat,dog,maeo'

So I want to use my wordSearch to find the word match in my array. In this case, after search in my array base on wordSearch, that 3 word in my WordSearch which is 'tom, cat and dog' that actually found in the array. And only one that didn't match with the array. Can some one help me to set a counter to iterate the wordSearch compare with the arr, the output should be the number of the word that didn't found in the arr. Thank you!

Answer 1

[KSSV]

str = 'cat;tom;jerry;dog;cat' ;

numel(regexp(str,'cat')) % cat
numel(regexp(str,'dog')) % dog
numel(regexp(str,'tom')) % tom

[Tech VNGS]

Do you know the other way to do it with loop and if else?

[KSSV]

loop for?

[Tech VNGS]

for the same problem above by using loop. One more question, for the one you commented above, is there anyway can you print out the one that not found in the array? for example I call numel(regexp(str,'meor')) which is not found in the array. then print out the word meor.

[KSSV]

str = 'cat;tom;jerry;dog;cat' ;
s = {'cat','dog','tom','meor'} ;

count = zeros(size(s)) ;
for i = 1:length(s)
    count(i) = numel(regexp(str,s{i})) ;
    fprintf('%s found for %d times\n',s{i},count(i)) ;
end

[Tech VNGS]

Thank you very much. I got it now. Really appreciate about that.

Answer 2

[Walter Roberson]

Hint: split the strings into parts, and setdiff()