open R2017a Simulink Model into R2015b
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I have a model that is done in MATLAB Simulink R2017a and I want to open it in MATLAB Simulink R2015b. Unfortunately, I don't have 2017 version so I can export it to previous version. is there any way for doing this?
5 件のコメント
dhruv gajwa
2019 年 11 月 25 日
Simulink has a preference, in the Model File section, called "Do not load models created with a newer version of Simulink". You can temporarily turn this off rather than edit the model files to change version numbers.
If the model uses only basic blocks then it might be possible to load it in R2017b, but it could also crash MATLAB. As others have commented, using the "Export to Previous Version" feature is the supported way to take a model from a later release to an earlier one.
Remember to turn the preference "Do not load models created with a newer version of Simulink" back on afterwards.
Muhammad Zeeshan Ahmed Khan
2020 年 12 月 31 日
https://www.mathworks.com/help/simulink/slref/simulink.exporttoversion.html#d122e311637
回答 (2 件)
Marco
2017 年 10 月 9 日
編集済み: Marco
2017 年 10 月 9 日
Hello, I think that that the link could be useful in order to solve your problem: https://it.mathworks.com/matlabcentral/answers/94724-how-can-i-open-my-current-simulink-models-in-previous-versions-of-simulink
BR Marco
3 件のコメント
Marco
2017 年 10 月 9 日
Yes, you are right. The only possibility is to have a newer version of Matlab.
dhruv gajwa
2019 年 11 月 25 日
Simulink has a preference, in the Model File section, called "Do not load models created with a newer version of Simulink". You can temporarily turn this off rather than edit the model files to change version numbers.
If the model uses only basic blocks then it might be possible to load it in R2017b, but it could also crash MATLAB. As others have commented, using the "Export to Previous Version" feature is the supported way to take a model from a later release to an earlier one.
Remember to turn the preference "Do not load models created with a newer version of Simulink" back on afterwards.
Sri Harish
2019 年 2 月 9 日
clear all
clc
syms t s y(t) Y
dy(t)=diff(y(t));
d2y(t)=diff(y(t),2);
F = input('Input the coefficients [a,b,c]: ');
a=F(1);b=F(2);c=F(3);
nh = input('Enter the non-homogenous part f(x): ');
eqn=a*d2y(t)+b*dy(t)+c*y(t)-nh;
LTY=laplace(eqn,t,s);
IC = input('Enter the initial conditions in the form [y0,Dy(0)]: ');
y0=IC(1);dy0=IC(2);
LTY=subs(LTY,{'laplace(y(t), t, s)','y(0)','D(y)(0)'},{Y,y0,dy0});
eq=collect(LTY,Y);
Y=simplify(solve(eq,Y));
yt=simplify(ilaplace(Y,s,t));
disp('The solution of the differential equation y(t)=')
disp(yt);
ezplot(yt,[y0,y0+2]);
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