Simple question regarding bar plot with categorical data

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maho
maho 2017 年 10 月 6 日
コメント済み: Henry 2024 年 10 月 14 日
Hello guys,
I am new to matlab, and I'm trying to do a simple bar plot, like this:
x = ["bananas" "apples" "cherries"];
y = [14,12,7];
bar(categorical(x),y);
The problem is that bar() function seems to sort the x-labels in alphabetical order. Is there any way to override this behaviour, so that the x-labels are left in their original order?

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Sean de Wolski
Sean de Wolski 2017 年 10 月 6 日
編集済み: Sean de Wolski 2017 年 10 月 6 日
x = categorical(["bananas" "apples" "cherries"]);
x = reordercats(x,{'bananas' 'apples' 'cherries'});
y = [14,12,7];
bar(x,y);
Categoricals can have order associated with them (for the purpose of relational operators).
  7 件のコメント
Toshia M
Toshia M 2023 年 9 月 20 日
編集済み: Toshia M 2023 年 9 月 20 日
Starting in R2023b, you can specify x as a string vector (or a cell array of character vectors), and MATLAB preserves the order. For example:
x = ["bananas" "apples" "cherries"];
y = [14,12,7];
bar(x,y)
Henry
Henry 2024 年 10 月 14 日
Since you guys are fixing this. Could you also put in a ticket to fix this for the errorbar() plot

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その他の回答 (4 件)

Steven Lord
Steven Lord 2017 年 10 月 6 日
If you're using release R2016b or later you could use histogram with a vector of BinCounts instead of using bar.
x = ["bananas" "apples" "cherries"];
C = categorical(x);
y = [14,12,7];
h = histogram('Categories', C, 'BinCounts', y);

Souarv De
Souarv De 2021 年 4 月 8 日
編集済み: Souarv De 2021 年 4 月 8 日
I also faced the same issue. There are numerous shortcut techniques available to solve it out. What I used to follow is as below :
x = categorical(["bananas" "apples" "cherries"]);
x = reordercats(x,cellstr(x)');
y = [14,12,7];
bar(x,y);

Rik
Rik 2017 年 10 月 6 日
編集済み: Rik 2017 年 10 月 6 日
The problem is not in bar, but in categorical. I can't find in the doc how to preserve order (with unique I know there is a switch to do so). So my suggestion would be to convert it yourself:
[~,ia,~]=unique(x,'stable');
x2=1:length(x);
x2=x(ia);
bar(x2,y)
xticks(x2)
xticklabels(x)%might not work, as this expects a cell stray containing strings
Of course, your labels are very likely to be unique, otherwise bar wil most likely yield an error, so this should work the same in all valid situations:
x2=1:length(x);
bar(x2,y)
xticks(x2)
xticklabels(x)%might not work, as this expects a cell stray containing strings
  2 件のコメント
Rik
Rik 2017 年 10 月 6 日
xticklabels and xticks were introduced in R2016b, so for earlier releases you should use gca and set the XTick and XTickLabels properties.
maho
maho 2017 年 10 月 9 日
Thank you for your response, Rik!
Your solution works, but it doesn't produce the same graphical output as using bar() with a categorical 'x' variable. In particular, if you squash the graph window horizontally, so that it is tall and narrow, you see that:
bar() using categorical variables very cleverly rotates the labels so they don't mush together
bar() using xticklabels() not so cleverly mushes the labels together so they become unreadable. :(
The same thing happens if you have many columns in your bar chart in relation to the physical width of your graph.

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michael dupin
michael dupin 2022 年 10 月 3 日
編集済み: michael dupin 2022 年 10 月 3 日
*** Use histogram and not bar :)
I've been struggling with this until now, so sharing with the community. You can use the histogram simply as a drawing function, not actually counting anything.
Including the vertical bars as well (instead of "barh"), as long labels are typically better displayed horizontally.
Et voila! Good luck. Mike
x = ["bananas" "apples" "cherries"];
y = [14,12,7];
histogram('Categories',x,'BinCounts',y,'orientation','horizontal');
histogram('Categories',x,'BinCounts',y);

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