How to remove repeating rows without unique function?

I have a 624x2 matrix of ordered pairs, of which there are some repeating rows that I must remove. Is there a way to remove these repeating rows without using the unique function? Maybe using a for loop? The reason I can't use the unique function is because when I implement this matlab script in Simulink's Matlab Function block, the matrix must be sorted first before using the unique function. I can't sort the matrix because I will lose my ordered pairs and sortrows doesn't solve the issue either because I get the same error from Simulink.

 採用された回答

Cedric
Cedric 2017 年 9 月 25 日
編集済み: Cedric 2017 年 9 月 25 日

2 投票

Use the 'stable' option:
>> A = randi( 3, 10, 2 )
A =
2 3
1 1
3 1
3 1
3 1
3 3
3 3
2 1
2 3
1 1
>> unique( A, 'rows' )
ans =
1 1
2 1
2 3
3 1
3 3
>> unique( A, 'rows', 'stable' )
ans =
2 3
1 1
3 1
3 3
2 1

8 件のコメント

Andrew Poissant
Andrew Poissant 2017 年 9 月 25 日
I have tried using the stable option and am still getting the errror "The second operand is not sorted in ascending order. Use SORT first" in Simulink. The second operand is referring to my unique function call
Cedric
Cedric 2017 年 9 月 25 日
編集済み: Cedric 2017 年 9 月 25 日
I had never seen that. Here is another approach:
>> A = randi( 3, 10, 2 )
2 1
2 3
3 2
3 1
1 1
2 2
2 3
2 2
3 2
3 1
>> [A_s, id_s] = sortrows( A ) ;
[~, id_u] = unique( A_s, 'rows' ) ; % Passing sorted A to UNIQUE.
A_u = A(sort( id_s(id_u) ), :)
which outputs
A_u =
2 1
2 3
3 2
3 1
1 1
2 2
and just to check:
>> isequal( A_u, unique( A, 'rows', 'stable' ))
ans =
logical
1
So that seems to be working.
Note that Simulink users may know a better approach and/or why you seem to have to sort your data before you can use UNIQUE, because I have no clue!
Andrew Poissant
Andrew Poissant 2017 年 9 月 26 日
It is still giving me the same error. Sortrows does not work for sorting, Simulink needs the function SORT used for this. Is there any way to remove repeating rows without using unique at all?
Cedric
Cedric 2017 年 9 月 26 日
編集済み: Cedric 2017 年 9 月 26 日
It would be better if a Simulink specialist would kick in and explain how this can be done properly in Simulink. I can only find "tricks" to emulate what you don't seem to have.
Here is another one:
>> A = randi( 3, 10, 2 )
A =
3 1
3 3
1 3
3 2
2 3
1 1
1 2
2 3
3 3
3 3
>> checkFun = @(rowId) ~any(all(bsxfun(@eq, A(rowId,:), A(1:rowId-1,:)), 2)) ;
select = [true, arrayfun(checkFun, 2:size(A, 1))] ;
A_u = A(select, :)
which outputs:
A_u =
3 1
3 3
1 3
3 2
2 3
1 1
1 2
and to check:
>> isequal( A_u, unique( A, 'rows', 'stable' ))
ans =
logical
1
Andrew Poissant
Andrew Poissant 2017 年 9 月 26 日
Yes, that would be nice if someone versed in simulink could offer advice, but I appreciate your help. Unfortunately, Simulink matlab function block can't take function handles or use arrayfun either. It is extremely annoying how limited the block is
Cedric
Cedric 2017 年 9 月 26 日
編集済み: Cedric 2017 年 9 月 26 日
Then there is the good ol' loop:
A = randi( 3, 10, 2 ) ;
nRows = size(A, 1) ;
keep = true(nRows, 1) ;
for rowId = 2 : nRows
if any(all(repelem(A(rowId,:),rowId-1, 1) == A(1:rowId-1,:), 2))
keep(rowId) = false ;
end
end
A_u = A(keep,:) ;
Test:
>> isequal(A_u, unique(A, 'rows', 'stable'))
ans =
logical
1
If REPELEM is not supported, replace by REPMAT. If REPMAT not supported either, we can build the darn matrix using a product.
Andrew Poissant
Andrew Poissant 2017 年 9 月 26 日
It worked! Thank goodness. Really appreciate all of the help you gave me, you rock!
Cedric
Cedric 2017 年 9 月 26 日
My pleasure. The amount of unsupported features seems to be a real pain, good luck with the rest!

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その他の回答 (1 件)

Jan
Jan 2017 年 9 月 26 日
編集済み: Jan 2017 年 9 月 26 日

0 投票

I still do not understand, why you cannot simply sort the data. But this might be useful:
!!! UNTESTED !!!
function Data = UniqueRows2(Data)
nRow = size(Data, 1);
keep = true(nRow, 1);
for k1 = 1:nRow
if keep(k1)
for k2 = k1 + 1:nData
if keep(k2)
% For rows of length 2:
keep(k2) = (Data(k2, 1) ~= Data(k1, 1)) | (Data(k2, 2) ~= Data(k1, 2));
% General row length:
% keep(k2) = any(bsxfun(@ne, Data(k2, :), Data(k1, :)), 2);
end
end
end
end
Data = Data(keep, :);
end
This might be faster with vectorization:
function Data = UniqueRows(Data)
nRow = size(Data, 1);
keep = true(nRow, 1);
for k1 = 1:nRow
if keep(k1)
keep(k1 + 1:nData) = and(keep(k1 + 1:nData), ...
any(bsxfun(@ne, Data(k2, :), Data(k1, :)), 2));
end
end
Data = Data(keep, :);
end

1 件のコメント

Andrew Poissant
Andrew Poissant 2017 年 9 月 26 日
Thanks! This also worked well for me!

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