Help with For/If commands

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Jevin
Jevin 2012 年 4 月 18 日
I am working on a project right now, and have a menu asking what a user would like to solve for. The menu corresponds to function handles, and in the function handles the variables can be used in more than 1. What i want to do is to have it run for variable A or B or C, and if it doesn;t have A B or C in it, it will stop and move to D E and F.
Here is what some of the code looks like :
(choice is the variable i assigned for the menu)
if choice == 1,4;6;7;8;10;11;
a=input ('What is the cross sectional area? ');
else
end
if choice ==2,3;5;6;
cl=input('What is the change in length? ');
else
end

採用された回答

Junaid
Junaid 2012 年 4 月 18 日
Use switches .. I hope it will solve your problem.
ex.
switch choice
case {1,4,6,7,8,10,11}
% your code here
case {2,3,5,6}
% your code here
end
  1 件のコメント
Jevin
Jevin 2012 年 4 月 18 日
That seems to work at first, but later on i have something along the lines of :
if choice == 2||3||4||5||6||7;
l=input('What is the length of your object? ');
end
if choice == 8||9||11;
cp=input('How many points of contact does your object have? ');
end
if choice == 3||4||6||7;
em=input('What is the elastic modulus of your material? ');
so it needs to work for more than one, since i am asking the components of formulas, and 5 of the formulas share 1 variable etc.

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2012 年 4 月 18 日
switch choice
case {2, 3, 4, 5, 6, 7}
%your code here
end
switch choice
case {8, 9, 11}
%your code here
end
If you prefer to use "if":
if ismember(choice, [1 4 6 7 8 10 11])
%your code here
end
if ismember(choice, [8, 9, 11])
%your code here
end

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