Help on a problem

18 ビュー (過去 30 日間)
Gaëtan Poirier
Gaëtan Poirier 2017 年 9 月 22 日
コメント済み: Walter Roberson 2017 年 9 月 22 日
I have this problem and I'm wondering if anyone can help me to figure it out. It goes as follows: write a program to iteratively generate points in two-dimensional space using the following rules:
(x_{n+1},y_{n+1}) =
/ (0.5,0.27*y_n), with 2% probability;
|
| (-0.139*x_n + 0.263*y_n + 0.57, 0.246*x_n + 0.224*y_n - 0.036), with 15% probability;
<
| (0.17*x_n - 0.215*y_n + 0.408, 0.222*x_n + 0.176*y_n + 0.0893), with 13% probability;
|
\ (0.781*x_n + 0.034*y_n + 0.1075, -0.032*x_n + 0.739*y_n + 0.27), with 70% probability.
Start from an initial point (x_1,y_1)=(0.5,0.0). Carry out the iteration at least 30,000 times

採用された回答

Walter Roberson
Walter Roberson 2017 年 9 月 22 日
for iter = 1: 30000
r = rand() ;
if r < 0.02
....
elseif r < 0.02+0.15
.....
  3 件のコメント
Gaëtan Poirier
Gaëtan Poirier 2017 年 9 月 22 日
This is what I have so far, doesn't seem repeat 30000 times, only comes out with one varible in r, x, and y.
for iter = 1: 30000
r = rand();
x = 0.5;
y = 0;
if r < 0.02
y = y * 0.27*r;
elseif r < 0.02 + 0.15
x = x -0.139 * r + 0.246 * r;
y = y + 0.263 * r + 0.224 * r - 0.036;
elseif r < 0.02 + 0.15 + 0.13
x = x + 0.17 * r - 0.032 * r;
y = y + 0.034 * r + 0.739 * r + 0.27;
elseif r < 0.02 + 0.15 + 0.13 + 0.70
x = x + 0.781 * r - 0.032 * r;
y = y + 0.034 * r + 0.1075 + 0.739 * r + 0.27;
end
end
Walter Roberson
Walter Roberson 2017 年 9 月 22 日
x_ = 0.5;
y_ = 0;
for n = 1: 30000
r = rand();
if r < 0.02
y_(n+1) = y_(n) * 0.27*r;
elseif r < 0.02 + 0.15
x_(n+1) = x_(n) -0.139 * r + 0.246 * r;
y_(n+1) = y_(n) + 0.263 * r + 0.224 * r - 0.036;
etc
After all of that you are probably expected to do
scatter(x, y)

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeGet Started with MATLAB についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by