reduce the size of figure,

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simira atraqi
simira atraqi 2012 年 4 月 17 日
Hello Everyone, How can I reduce the size of figure in Matlab? Thanks

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Jakob Sørensen
Jakob Sørensen 2012 年 4 月 17 日
Then you are looking for some clever matrix work, rather than figure size.
Try smth like this:
wavelength = 100;
a = 1:4001;
A = repmat(a, [3001 1]);
B = 3.*(sin((1-A).*2.*pi./wavelength)) + 1003;
figure;
imagesc(B);
Takes less than a second to run on my computer and does around the same. You might have to fix the last couple of details for it to be an exact match.

その他の回答 (2 件)

Jakob Sørensen
Jakob Sørensen 2012 年 4 月 17 日
Here is an example:
% Create a 1000x500 px figure, at the position x,y = 10,10 (starting at the left
% bottom corner)
superFig = figure('Position', [10 10 1000 500]);
If you want to change it for an already existing figure you just use the set function.
% Changes properties of figure named 'superFig'
set(superFig, 'Position', [10 10 1000 500]);
or
% Changes properties of current figure
set(gcf, 'Position', [10 10 1000 500]);
  4 件のコメント
simira atraqi
simira atraqi 2012 年 4 月 17 日
figure(1);
imagesc(A);
simira atraqi
simira atraqi 2012 年 4 月 17 日
whos
Name Size Bytes Class
A 3001x4001 96056008 double array

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Jakob Sørensen
Jakob Sørensen 2012 年 4 月 17 日
Try this:
tic;
xRes = 1; % Sets the resolution (step length), in µm, along the x-axis.
yRes = 1; % Sets the resolution (step length), in µm, along the y-axis.
zRes = 1; % Sets the resolution (step length), in µm, along the z-axis.
xLength = 4000; % Sets the length of the surface in X.
yLength = 3000; % Sets the length of the surface in Y.
wavelength = 100;
f = @(x) 3*sin(x*2*pi/wavelength) + 1003; % The function for the sine wave with the
% amplitude 3 µm and wave length of about 100 µm. Mean level is
% 1003 µm.
% Prints the sine wave into a matrix:
A = zeros(yLength/yRes+1,xLength/xRes+1);
for k = 1:length(A(:,1))
for l = 1:length(A(1,:))
A(k,l) = f(l-1);
end
end
toc;
and then...
tic;
figure(1);
imagesc(A);
toc;
You will see that the plotting part only takes around 1/50 of the total time. What is taking so long is running a loop around 12 million times.
  1 件のコメント
simira atraqi
simira atraqi 2012 年 4 月 17 日
yes,
Elapsed time is 294.952000 seconds.
Elapsed time is 0.141000 seconds.
but I want to reduce the time for all the program not only for the figure.

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