error-index exceeds matrix dimension
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In the following code i get error a s
P1 = [-1 -1 2 2; 0 5 0 5];
Tar = [0 ;1 ]
indices=crossvalind('kfold',Tar,10);
for i=1:10
test=(indices==i);trains= ~test
tst = (indices==i);
val = (indices== mod(i+1,10));
trn = ~[tst,val];
net=newff(P1(:,trains),Tar(:,trains),2);
net=init(net);
[net,tr]=train(net,P1(:,trains),Tar(:,trains));
out = round(sim(net,P(:,test)));
end
Index exceeds matrix dimensions.
Error in cfour (line 58)
net=newff(P1(:,trains),Tar(:,trains),2);
please help
0 件のコメント
採用された回答
Walter Roberson
2012 年 4 月 17 日
That code is going to generate an error unless "indices" is of length 1 exactly. If it is longer than 1, then "test" and "train" will be longer than 1, and would then be too long to use as logical vectors against the columns of the single-column Tar array.
その他の回答 (2 件)
Andreas Goser
2012 年 4 月 17 日
net=newff(P1(:,trains),Tar(:,trains),2);
throws an error in the first run, as Tar has no second dimension. Probably you mean:
net=newff(P1(:,trains),Tar(trains),2);
3 件のコメント
Andreas Goser
2012 年 4 月 17 日
You just asked why you got this error. Now you know ;-)
I may know more about MATLAB, but hope fully you know more about neural networks... The message "Inputs and targets have different numbers of samples." That sounds like an actionable error message, isn't it?
Greg Heath
2012 年 4 月 22 日
1. The input and target matrices must have the same number of columns:
Tar = [ 0 0 1 1 ]
[ I N ] = size( P1) % [ 2 4 ] [ O N ] = size(Tar) % [ 1 4 ]
k = 10
indices=crossvalind('kfold',Tar,k)
2. a. It doesn't make sense to use k > N
b.Instead of using CROSSVALIND from the Bioinformatics TBX, the algorithm
might be more portable if you use CROSSVAL from the Statistics TBX.
3. trains= ~test
Rename. TRAINS is a MATLAB function.
Hope this helps.
Greg
2 件のコメント
Greg Heath
2012 年 4 月 22 日
Typical nontrivial classification examples should have classes with
many more I/O training pairs than input dimensions.
For the FisherIris example/demo (c = 3, I = 4, N = 150).
Although that ratio is
N/(3*4) = 12.5,
the scatter plot in the PetalLength/PetalWidth plane indicates
that the 3 classes are linearly separable with two hidden nodes.
Hope this helps.
Greg
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