can anyone provide a code for converting 2d point into 3d cordinate system

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praveen rai
praveen rai 2017 年 9 月 13 日
コメント済み: Rik 2017 年 9 月 15 日
i want to map the 2d point into 3d cordinate usinf direct linear transformation algo(DLT) or using homography I am not sure how to do or which method shd i do I want the code with brief xplanation for eg i have (x1,y1),(x2,y2)...x and y denote cordinate and with ref to d same point i want in object space i.e (x,y,z) coordinate
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praveen rai
praveen rai 2017 年 9 月 15 日
@ rik Wisselink i guess exactly what u are saying is right.I have used single camera i have the data set can u provide me code for this prob so that i can put the values and get my result or u need the data sets and image.. @image analyst i have accepted his ans for his explanation i didnt get what i want..rik understand my prob just i want from him what he said can he provide me the code
Rik
Rik 2017 年 9 月 15 日
You just got upgraded from unintelligible to a case of doit4me. Read those links I gave you and then follow my suggestion from the second comment:
"You should at the very least provide the image you are working on, because that is a very difficult problem, which may not be possible with your data. I have little experience with computer vision, but usually it uses two cameras side by side or a single camera whose movements are known."
I don't know much about computer vision, but if I were you I would start Googling examples until you have something that is close to working. As you know the name from a specific algorithm, I suspect you are in some educational program or course. If that's the case, ask your teacher/instructor for help. It seems you need more than what you can reasonably expect to get here.

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採用された回答

John D'Errico
John D'Errico 2017 年 9 月 13 日
Sure. Trivial to do, in fact.
xy2xyz = @(x,y) [x,y,1];
For any value of x and y, this creates a new set of coordinates in the R^3 (x,y,z) domain.
It is a rather boring transformation, but it satisfies the requirements. I suppose you could have done something more exciting. Perhaps...
xy2xyz = @(x,y) [x,y,randn()];
or
xy2xyz = @(x,y) [x,y,x+2*y];
The latter can be written as
xy2xyz = @(x,y) [x,y]*[1 0 1;0 1 2];
Any of infinitely many transformations will exist. What you have not said is what mapping is appropriate.
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praveen rai
praveen rai 2017 年 9 月 13 日
ya u r right.. right word is mapping but dis transformation i dont need i wl find some solution..i want to do with DLT algorithm it contain so many parameters i know d algo but want to implement in matlab
John D'Errico
John D'Errico 2017 年 9 月 13 日
But only you know what you want to do. So only you can write the code.

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その他の回答 (1 件)

Image Analyst
Image Analyst 2017 年 9 月 13 日
I don't exactly know what you want, but perhaps you're thinking of colorcloud().
  2 件のコメント
praveen rai
praveen rai 2017 年 9 月 13 日
no no m not thnkng of color cloud i want 2d coordinates convert into 3d coordinate..let me xplain u know image is 2d plane but d real world is 3d (x,y,z) i.e cartesian plane converts to (x,y) i.e 2d/image plane but i want 2d plane to 3d plane means image plane to cartesian plane..now u got it or still not clear i have also mention d algo name i.e DLT

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