Plot Matrix Columns in a Loop
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I have matrix X which is 225 by 6. And vector y which is 225 by 1. y is a binary with values 0 or 1. What I need to accomplish is to plot every column in X with y seperately.
Just a short example For instance:
x1 x2 x3 (x4 -x6)etc y
26 0,01 -1,15 0
25 0,025 1,58 1
20 0,185 2,57 1
I need to plot x1 with y, x2 with y etc... for pos=find(y==1) and neg=find(y==0)
I only accomplished to plot all column with y. But the is not satisfactory because the columns in X have different ranges of values.
*function plotData(X,y)*
pos = find(y==1);
neg = find(y==0);
plot(X(pos,1),X(pos,2),X(pos,3),X(pos,4),X(pos,5),X(pos,6),'kx','MarkerSize',5,'Color','s')
hold on
plot(X(neg,1),X(neg,2),X(neg,3),X(neg,4),X(neg,5),X(neg,6),'ko','MarkerSize',5,'Color','r')
*end*
But this way it plots all columns at once. How can I do it seperately?
Thanks in advance.
4 件のコメント
I don't get it. You already have the logical index:
plot(x(y,:))
hold on
plot(x(~y,:))
What really baffles me is what you expect this plot to show: what is the reason for this indexing?
JacquelineK
2017 年 9 月 10 日
JacquelineK
2017 年 9 月 10 日
回答 (1 件)
Jose Marques
2017 年 9 月 10 日
Hello, Jacqueline Kpognon. Do you want to differents figures? Try this:
pos = find(y==1);
neg = find(y==0);
plot(X(pos,1),X(pos,2),X(pos,3),X(pos,4),X(pos,5),X(pos,6),'kx','MarkerSize',5,'Color','s')
figure();
plot(X(pos,1),X(pos,2),X(pos,3),X(pos,4),X(pos,5),X(pos,6),'ko','MarkerSize',5,'Color','r')
1 件のコメント
JacquelineK
2017 年 9 月 10 日
編集済み: Cedric
2017 年 9 月 10 日
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