Hi, I have a 3 by 3 matrix X(a,b,c)
I tried to define a submatrix
S = X(3,:,:);
but matlab keeps saying that S is not a 2D array. Why is that so?
Thank you very much.
Added: class(S) apparently is "double" but I don't understand why. How might I make S into a 2D array?

4 件のコメント

Oleg Komarov
Oleg Komarov 2012 年 4 月 15 日
X is a 3D array if you write it in that way: X(a,b,c).
what whos on X returns?
Werner
Werner 2012 年 4 月 15 日
Thank you, @Oleg, but wouldn't S (havin one coordinate fixed), be a 2D array?
Werner
Werner 2012 年 4 月 15 日
@Oleg: Also, if S as defined is not a 2D array, how might I define a 2D array that is essentially the same thing as S? Thanks.
Walter Roberson
Walter Roberson 2012 年 4 月 15 日
Werner, X(3,:,:) is a 1 x something x something array. See IA's solution.

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 採用された回答

Image Analyst
Image Analyst 2012 年 4 月 15 日

0 投票

Use squeeze(). This works fine for me:
s3D = rand(4,3,2)
s2D = squeeze(s3D(2,:,:))
s3D(:,:,1) =
0.5103 0.0183 0.1749
0.6590 0.7794 0.2998
0.8773 0.6623 0.7778
0.0790 0.9458 0.6653
s3D(:,:,2) =
0.2475 0.0516 0.3926
0.7406 0.1848 0.6212
0.0042 0.7256 0.4685
0.5316 0.3404 0.1957
s2D =
0.6590 0.7406
0.7794 0.1848
0.2998 0.6212
You can see that it took row 2 out of the first plane, and row 2 out of the second plane, and gave you a 3 by 2 array, just what it should have.

1 件のコメント

Werner
Werner 2012 年 4 月 15 日
Thank you !

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