Average wind speed histogram

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Dimitrios Bentis
Dimitrios Bentis 2017 年 8 月 31 日
コメント済み: José-Luis 2017 年 8 月 31 日
My dataset consists of a time vector (30min step) a vector of wind speeds and a vector of wind directions.
I find the cases when wind direction is, for example, nort-northeast using x=find(WD>0&WD<60
and then i use histogram(T.Hour(x),[0 2 4 6 8 10 12 14 16 18 20 22 24]) to derive to a histogram of absolute frequencies of the north-northeast wind in each of the 2hour bins.
How can i plot a histogram with the average wind speed of this specific wind in each 2hour interval?

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José-Luis
José-Luis 2017 年 8 月 31 日
t1 = datetime(2016,6,1,0,30,0);
t2 = datetime(2017,5,31,23,30,0);
t = t1:minutes(30):t2;
wind_dir = randi(360,numel(t),1);
wind = rand(numel(t),1);
idx = wind_dir >= 320 & wind_dir <=360;
t_sub = t(idx);
wind_sub = wind(idx);
result = accumarray(hour(t_sub).' + 1, wind_sub,[],@mean);
bar(result)
  2 件のコメント
José-Luis
José-Luis 2017 年 8 月 31 日
result = accumarray(ceil((hour(t_sub)+1)./2).' , wind_sub,[],@mean);

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その他の回答 (1 件)

José-Luis
José-Luis 2017 年 8 月 31 日
You could adapt a rose plot to your need. It is the "standard" way of showing wind direction distributions.
  5 件のコメント
Dimitrios Bentis
Dimitrios Bentis 2017 年 8 月 31 日
i have defined my time vector (t) as follows:
t1 = datetime(2016,6,1,0,30,0);
t2 = datetime(2017,5,31,23,30,0);
t = t1:minutes(30):t2;
the data that i have are 2 vectors corresponding to wind speed and direction (WS, WD)
then i used:
x=find(WD>=320&WD<=360);
to find when the desired wind occurs. then with
histogram(t.Hour(x),[0 2 4 6 8 10 12 14 16 18 20 22 24]);
i take the histogram i show above.
what i would like to plot now is the average wind speed of each the bins in the histogram above. In that histogram the bins represent frequency of occurrence.
Thank you for your fast responses.
*if something is unclear ask for clarification.

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