フィルターのクリア

Splitting a table to 2

8 ビュー (過去 30 日間)
Rafi Kandli
Rafi Kandli 2017 年 8 月 16 日
コメント済み: KL 2017 年 8 月 16 日
Hello all, I have a table named A. I want to split it into 2 sub-tables: Table 1 has 60% of the rows in A, chosen randomly. Table 2 has all the other rows that are not in table 1. Any elegant idea on how to do this?

採用された回答

KL
KL 2017 年 8 月 16 日
dummy = 10*rand(10,4);
T = array2table(dummy)
ranRows = randperm(length(dummy));
T1 = T(ranRows(1:(0.6*length(dummy))),:)
T2 = T(ranRows((0.6*length(dummy))+1:end),:)
  2 件のコメント
Guillaume
Guillaume 2017 年 8 月 16 日
The proper function for getting the height of a table is height, so:
ranrows = randperm(height(T));
T1 = T(ranRows(1:0.6*height(T)), :);
T2 = T(ranRows(0.6*height(T)+1:end), :);
To avoid a warning, I would also wrap the 0.6*height(T) calculation inside a ceil, a floor or a round.
KL
KL 2017 年 8 月 16 日
Thanks Guillaume!

サインインしてコメントする。

その他の回答 (2 件)

Adrian
Adrian 2017 年 8 月 16 日
編集済み: Adrian 2017 年 8 月 16 日
Note that this will only play nicely if you have a reasonably large array.
selection = randi([1 10], size(A,1),1)
A_sixty = A(selection>4);
A_forty = A(selection<=4);

Sean de Wolski
Sean de Wolski 2017 年 8 月 16 日
If you're looking to split your data into a training and testing set, then it might pay to look at cvpartition as well, it provides more options for splitting tables.

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by