How get one element of a vector one by one in each iteration of for loop?

rowKernel(1) is just getting one element from rowKernel which I load it before. I need to get all element from rowKernel file, but one by one in each iteration, means each ROW in each iteration should include one elements. Could you please let me know how can I write the code by this way. Now, I have in each iteration just first value in rowKernel and colKernel, but I need all of them which they are 180 values, but as I said I need them one by one in each iteration. Thank you.

load rowKernel

load colKernel

row = 0; 

for ROW = rowKernel(1) 

      row = row + 1;    

      BM.KernelY(row,1) = ROW;  

      col = 0;
      for COL = colKernel(1)
          col = col + 1;
          BM.KernelX(col,1) = COL;
          BM.KernelY_Global (ROW,COL) = row;
          BM.KernelX_Global (ROW,COL) = col;

      end
  end

[KSSV]

If you have a matrix of size mxn..you can get each elements in loop using:

for i = 1:m
    for j = 1:n
         A(i,j)
     end
end

[Neda]

As I said rowKernel and colKernel are vectors, and I need one elements back in each iteration, for example, If I write like below, the ROW result in each iteration is a vector, but I need one scalar value back to me in each iteration. thanks

      for  ROW = rowKernel(1:180) 
      row = row + 1;    
      BM.KernelY(row,1) = ROW;

[Sangeetha Jayaprakash]

I understand that "rowKernel" is a vector of size N and you would like to get one element from that vector in each iteration.

This can be done as follows:

for r_idx = 1:N
   element = rowKernel(r_idx); 
end