Averaging sequential data if values are the same?

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yz
yz 2017 年 8 月 10 日
コメント済み: yz 2017 年 8 月 11 日
I want to be able to average the values of an array of n rows and 5 columns, based on the repeated values of a specific column.
I only want to average the values that are next to each other and not all that repeat. Such that:
%Original data:
key_column = [-6 -6 -6 -6 -5 -5 -3 -3 -3 -1 -1 -1 0 0 1 1 2 2 2 3 3 5 5 5 5 6 6 6 6 4 4 4 3 3 3 3 3 3 3 2 2 2 1 1 1 1 0 0 -1 -1 -2 -3 -5 -5 -5 -5 -5 -5 -5 -6 -6 -6];
%Ends up as:
key_column_avg = [-6 -5 -3 -1 -0 1 2 3 5 6 4 3 2 1 0 -1 -2 -3 -5 -6]
I'm running into trouble because the values of the repeated numbers appear at multiple points in the column and I only want the to be averaged if they are "next to each other" on the column. Also, I'm having issues because the number of repeated values isn't the same for each number. Sometimes the value repeats for 10 times, sometimes for 3, sometimes for 7, sometimes for 4.
Is it possible to do this?
Thank you.
  4 件のコメント
yz
yz 2017 年 8 月 10 日
No, I want to average all columns based on the repeated sequential values of this specific column.
yz
yz 2017 年 8 月 10 日
Attached is a sample of my data set. Column 4 is the column of interest for the averaging, but I wish to apply the averaging to all columns (based on the n number of values on column 4)

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採用された回答

Andrei Bobrov
Andrei Bobrov 2017 年 8 月 10 日
key_column_avg = key_column(diff([0,key_column(:)'],1,2) ~= 0);
  4 件のコメント
Andrei Bobrov
Andrei Bobrov 2017 年 8 月 10 日
編集済み: Andrei Bobrov 2017 年 8 月 10 日
d = data_example;
g = cumsum(diff([0;d(:,4)]) ~= 0);
out = splitapply(@mean,d,g);
or
d = data_example;
g = cumsum(diff([0;d(:,4)]) ~= 0);
[gg,c] = ndgrid(g,1:size(d,2));
out1 = accumarray([gg(:),c(:)],d(:),[],@mean);
yz
yz 2017 年 8 月 11 日
Thank you so much!

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その他の回答 (2 件)

KL
KL 2017 年 8 月 10 日
key_column_avg = key_column(diff([0 key_column])~=0);

José-Luis
José-Luis 2017 年 8 月 10 日
key_column = [-6 -6 -6 -6 -5 -5 -3 -3 -3 -1 -1 -1 0 0 1 1 2 2 2 3 3 5 5 5 5 6 6 6 6 4 4 4 3 3 3 3 3 3 3 2 2 2 1 1 1 1 0 0 -1 -1 -2 -3 -5 -5 -5 -5 -5 -5 -5 -6 -6 -6];
result = [key_column(diff(key_column) > 0), key_column(end) ]

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