Convert plotted graph to (x,y) coordinates?
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Hi all,
I have a plotted graph and I wanted to know if it is possible to "convert" the plot by the graph() function to a plot in a (x,y) axis (like a scatter plot), but it is very important that is preserves the look of the plot! Is this possible in any way?
Thank you very much!
16 件のコメント
KSSV
2017 年 8 月 9 日
If you have data (x,y) in hand....use scatter
Felipe Schuback
2017 年 8 月 9 日
José-Luis
2017 年 8 月 9 日
You could use quiver() and superimpose it to your plot.
Felipe Schuback
2017 年 8 月 9 日
Felipe Schuback
2017 年 8 月 9 日
Felipe Schuback
2017 年 8 月 10 日
José-Luis
2017 年 8 月 10 日
Not gonna happen automagically, please see answer below.
You choose the direction by defining the starting point and the vector direction. I don't think it's just an option you can change. You'd need to reverse that.
Please accept the answer that best solves your problem.
Walter Roberson
2017 年 8 月 10 日
You asked about the solid head in a new Question. I answered there:
h = quiver(...., 'LineStyle', '--') %use the linestyle appropriate for the body
h.Head.LineStyle = 'solid'; %magic property, magic property value, notice this is not '-'
José-Luis
2017 年 8 月 10 日
I stand corrected. It apparently can happen automagically.
Only downside to it being undocumented is that it's, well, undocumented and can change without warning in a new release.
Prettier than my answer though.
Felipe Schuback
2017 年 8 月 11 日
Walter Roberson
2017 年 8 月 11 日
The "Head" property of quiver objects is not documented.
Felipe Schuback
2017 年 8 月 11 日
Walter Roberson
2017 年 8 月 11 日
Sorry, only one color is possible for any one call to scatter()
Felipe Schuback
2017 年 8 月 11 日
Walter Roberson
2017 年 8 月 11 日
Ah yes, I forgot for a moment about specifying the individual colors for scatter().
scatter() plots do not have line colors.
If you are referring to quiver(), then you can use the 'Color' option to set the same color for all of the lines; however, it is not possible to use different colors for different lines in any one quiver() call.
回答 (1 件)
José-Luis
2017 年 8 月 10 日
It ain't pretty but it works. As far as I understand there are no simple options you can set to get the look you want.
data = rand(10,4);
qH = quiver(data(:,1),data(:,2),data(:,3),data(:,4),0);
hold on
qH1 = quiver(data(:,1),data(:,2),data(:,3),data(:,4),0);
colorVector = rand(1,3);
qH2 = quiver(data(:,1),data(:,2),data(:,3),data(:,4),0);
colorVector = rand(1,3);
qH.LineStyle = '-';
qH.Color = colorVector;
qH1.LineStyle = '-';
qH1.Color = 'w';
qH1.ShowArrowHead = 'off';
qH2.LineStyle = '--';
qH2.Color = colorVector;
qH2.ShowArrowHead = 'off';
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